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Eva8 [605]
3 years ago
8

In this fulcrum, for the weights to be balance, what do the distances d1 and d2 have to be if the overall length is 12 feet?

Mathematics
2 answers:
mel-nik [20]3 years ago
5 0
For the fulcrum to balance, the product of weight and distance on both sides of the fulcrum must be the same.

Let d1= x. since total distance is 12, we can write d2 = 12 - x

for the fulcrum to balance:

60x = 50(12 - x)

60x = 600 - 50x

110x = 600

x = 5.45

Thus, d1= 5.45
and
d2= 12 - d1 = 12 - 5.45 = 6.55

d1 = 5.45
d2 = 6.55
eimsori [14]3 years ago
4 0
For this case we have the following system of equations:
 Equilibrium equation:
 60 * d1 = 50 * d2
 Total distance:
 d1 + d2 = 12
 Solving the equations we have:
 d1 = 5.45 feet
 d2 = 6.55 feet
 Answer:
 
the distances d1 and d2 have to be:
 d1 = 5.45 feet
 d2 = 6.55 feet
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We have the rate of descend as 44 feet in 4 sec.

So, in 1 second it will be = 44 / 4 = 11 feet.

Which is the unit rate.

Therefore, the unit rate of descend for the parachutist is 11 feet per second.

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\left\{ \begin{array} { l } { 4 x + y = 9 } \\ { 3 x - 2 y = 4 } \end{array} \right.

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