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nikitadnepr [17]
3 years ago
9

Find an equation for the plane that passes through the point (3, 6, −9) and is perpendicular to the line v = (0, −9, 5) + t(1, −

2, 3).
Mathematics
1 answer:
raketka [301]3 years ago
3 0
Y=4x over 9 should be the anwser if i did it right
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According to DeMorgan 's theorem, the complement of W · X + Y · Z is W' + X' · Y' + Z'. Yet both functions are 1 for WXYZ = 1110
sergeinik [125]

Answer:

The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.

Step-by-step explanation:

According to DeMorgan's Theorem:

(W.X + Y.Z)'

(W.X)' . (Y.Z)'

(W'+X') . (Y' + Z')

Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.

For the original function:

(W . X + Y . Z)'

= (1 . 1 + 1 . 0)

= (1 + 0) = 1

For the compliment:

(W' + X') . (Y' + Z')

=(1' + 1') . (1' + 0')

=(0 + 0) . (0 + 1)

=0 . 1 = 0

Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.

Without the parenthesis the compliment equation looks like this:

W' + X' . Y' + Z'

1' + 1' . 1' + 0'

0 + 0 . 0 + 1

Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.

Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.

3 0
3 years ago
Help me plzzzzzzzzzzz
Brrunno [24]

Answer:

i know the answer it is the second one dude if i am wrong sorry

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
A ball moves in a straight line has an acceleration of a(t) = 2t + 5. Find the position function of the ball if its initial velo
Vlad1618 [11]

Answer:

s(t) = frac{t^3}{3} + \frac{5t^2}{2} - 3t + 12

Step-by-step explanation:

Relation between acceleration, velocity and position:

The velocity function is the integral of the acceleration function.

The position function is the integral of the velocity function.

Acceleration:

As given by the problem, the acceleration function is a(t) = 2t + 5

Velocity:

v(t) = \int a(t) dt = \int (2t+5) dt = \frac{2t^2}{2} + 5t + K = t^2 + 5t + K

In which K is the constant of integration, which is the initial velocity. So K = -3 and:

v(t) = t^2 + 5t - 3

Position:

s(t) = \int v(t) dt = \int (t^2 + 5t - 3) = \frac{t^3}{3} + \frac{5t^2}{2} - 3t + K

In which K, the constant of integration, is the initial position. Since it is 12:

s(t) = frac{t^3}{3} + \frac{5t^2}{2} - 3t + 12

4 0
3 years ago
The price that a company charged for a computer accessory is given by the equation 100-10x^2 where x is the number of accessorie
Mashutka [201]

Answer:

i am not sure maybe look it up on google

Step-by-step explanation:

6 0
3 years ago
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Jenny is painting a toy chest that she made for her little brother. If the box is 3 feet long, 2 feet wide, and 3 feet tall, wha
statuscvo [17]

Answer:

42 ft squared

Step-by-step explanation:

here is a handy surface area calculator I use:

https://www.calculatorsoup.com/calculators/geometry-solids/surfacearea.php

3 0
3 years ago
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