Answer:
0.
Step-by-step explanation:
The angle whose sine is 5/12 = 22.62 degrees and in Quadrant II it is
180 - 22.62 degrees
The angle whose tan is (5/12) = 22.62.
So we can write α as 180 - α and β as α.
sin (α+β) = sin ( 180 - α = α) = sin 180
= 0.
Then d = e by transitive property
B the person above me is right
Answer:
Since the focus is at (-6,-11) and the directrix is at y=9:
The vertex is halfway between the focus and the directrix, so the vertex is at (-6,-1). (Draw this on graph paper if that doesn't make sense.)
The general form (conics form) of a parabola: 4p(y-k)=(x-h)^2 (vertex is (h,k) and "p" is the distance between the focus and vertex (or between vertex and directrix)).
(h,k) = (-6,-1)
p = 10 (distance between focus and vertex), so 4p = 40.
Therefore:
40(y+1)=(x+6)^2
Or if you need to rearrange to "vertex form": y=(1/40)(x+6)^2 - 1
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
