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Neporo4naja [7]
3 years ago
7

HELPPPPPPPPP 55 POINTS Isabel graphed the following system of equations.

Mathematics
1 answer:
Arturiano [62]3 years ago
5 0

Answer:

1.  Substitute y = -3x +4 for y in the first equation

2.  Combine like terms and isolate x

3.  Substitute in x into the 2nd equation to get y

Step-by-step explanation:

1.  Substitute y = -3x +4 for y in the first equation

2x- (-3x+4) = 6

2.  Combine like terms

5x -4 = 6

5x -4 +4 = 6+4

5x=10  Divide by 5 to isolate x

5x/5 =10/5

x=2

3. Substitute in x into the 2nd equation to get y

y = -3x +4

y = -3(2) +4

y = -6+4

y=-2

(2,-2)

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6 0
3 years ago
Read 2 more answers
18) through: (-3,-3), parallel to y = -x + 3​
otez555 [7]

Step-by-step explanation:

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6 0
3 years ago
Find the height of a right square pyramid that has a rectangular base area of 70 square units and a volume of 140 cubic units.
Lostsunrise [7]

Answer:

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5 0
3 years ago
3(9x-9)=16+3(-2x+9) please help me
Maru [420]
<span>3(9x-9)=16+3(-2x+9)
27x - 27 = 16 - 6x + 27
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5 0
3 years ago
At what values of x does f(x) = x^3 - 2x^2 -4x+1 satisfy the mean value theorwm on [0,1]
denis-greek [22]

Answer:

x=1/3

Step-by-step explanation:

A function f is given as

f(x) = x^3-2x^2-4x+1 in the interval  [0,1]

This function f being an algebraic polynomial is continuous in the interval [0,1] and also f is differntiable in the open interval (0,1)

Hence mean value theorem applies for f in the given interval

f(1) = 1-2-4+1 = -4\\f(0) = 1

The value

\frac{f(1)-f(0)}{1-0} =\frac{-4-1}{1} =-5

Find derivative for f

f'(x) = 3x^2-4x-4

Equate this to -5 to check mean value theorem

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We find that 1/3 lies inside the interval (0,1)

4 0
3 years ago
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