We are given

We can write it as

we can see that 2y is in first two terms
and -8 is in last two terms
so, we can factor it out

now, we can see that x+4 is common in both terms
so, we can factor it out

we can see that
x+4 is one of factor of terms
so, option-B..........Answer
Answer:
Step-by-step explanation:
You can start this in may ways but let's start by isolating one of the parenthesis:
x (x² - 5) = - (x - 3)
x³ - 5x = -x + 3 (here I multiplied x for what's inside the parenthesis and the "minus" signal by the other parenthesis which was (x - 3))
x³ - 5x + x = 3
x³ -4x = 3
x³ -4x -3 = 0 (now this right here is a "depressed cubic equation" and it's one of the toughest sit of all time, so good luck with that, you might wanna take a look at this:
ytb/watch?v=rNDy2ZFvG1E
or maybe I'm doing something wrong and it's simpler than that, but whaterver...)
Answer:
Standard score z=0.07
Step-by-step explanation:
The z-score, or standard score, represents an equivalent value for X but in the standard normal distribution, where μ=0 and σ=1.
For X=28.3 in a normal distribution with μ=26.3 and σ=28.1, the standard score can be calculated as:

This value is 0.07 standard deviations right to the mean.
In the picture attached, we have located the z-score.
(-1.15)x3.2=
-3.68
Alright so I got -3.68 by multiplying -1.15x3.2. We get a negative number since the first number is negative.
Answer:
<em>Choice: B.</em>
Step-by-step explanation:
<u>Operations With Functions</u>
Given the functions:
![f(x)=\sqrt[3]{12x+1}+4](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4)

The function (g-f)(x) can be obtained by replacing both functions and subtracting them as follows:

![(g-f)(x)= \log(x-3)+6 - (\sqrt[3]{12x+1}+4)](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%28%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4%29)
Operating:
![(g-f)(x)= \log(x-3)+6 - \sqrt[3]{12x+1}-4](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D-4)
Joining like terms:
![\boxed{(g-f)(x)= \log(x-3) - \sqrt[3]{12x+1}+2}](https://tex.z-dn.net/?f=%5Cboxed%7B%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D%2B2%7D)
Choice: B.