Difference between the area of the triangle and square is 25
Step-by-step explanation:
- Step 1: Find the area of the triangle given its 3 sides using the Heron's formula.
Area of the triangle = 
where s = 
⇒ s = (6 + 8 + 10)/2 = 24/2 = 12
= 
= 
= 
= 24 sq. units
- Step 2: Find the area of the square with perimeter = 28 units.
Perimeter of the square = 4 × side = 28
⇒ Side of the square = 28/4 = 7 units
⇒ Area of the square = (side)² = 7² = 49 sq. units
- Step 3: Find the difference between the area of the square and triangle.
Difference = 49 - 24 = 25
Answer:
D'(-6,-4)
Step-by-step explanation:
When making this non rigid transformation about a point, keep in mind that a dilation by a certain scale factor can be represented by:
Answer:
54
Step-by-step explanation:
please but me a crown
You use the equation Ax^2 + Bx + C to solve this equation.
The answer is 25.
I hope this helps :D
The inverse functions of sine, cos and tan functions are csc, sec and cot respectively.
<u>Step-by-step explanation:</u>
The reciprocals of sine, cos and tan functions are csc, sec and cot functions. The reciprocal of cosine function is secant, (sec) sec θ = 
The inverse or reciprocal function is cosecant (csc), 
The inverse tangent function is cotangent (cot) , expressed in two ways: 
or 
So 
then its reciprocal or inverse is termed as cot θ.
