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Nataly_w [17]
3 years ago
11

Suppose that in a large company, 30% of the computers are infected by adware. if 6 computers are randomly selected and tested, w

hat is the probability that 2 of the computers are infected by adware?
Mathematics
1 answer:
bazaltina [42]3 years ago
6 0
It's either 1.8 or 0.9
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17. Let A denote the event that the next request for assistance from a statistical software consultant relates to the SPSS packa
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Answer:

a. The probability is not equal to 1

b. P (A') = 0.70

c. P ( A U B ) = 0.80

d. P ( A' ∩ B' ) = 0.20

Step-by-step explanation:

a. Because these A and B are disjoint

b. since the probability of  A is 0.30 then the probability of A compliment is

    P(A compliment ) = 1 - P (A)

    P(A compliment ) = 1-0.30

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c. Since event are disjoint then intersection of A and B is 0, so probability of A U B is;

       P ( A U B ) = P (A) + P(B) - P(A∩ B)

       P ( A U B ) = 0.30 + 0.50 - 0

       P ( A U B ) = 0.80

d. The inetrsection of compilments of A and B are:

by using De Morgan's Law we have,

                     P ( A' ∩ B' ) = P [(A U B )']

                     P ( A' ∩ B' ) = 1 - P ( A U B )

                     P ( A' ∩ B' ) = 1 - 0.80

                     P ( A' ∩ B' ) = 0.20

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if (1,-7) is in the solution area of the inequality y ≤ 1x + b, what is the smallest value of b possible?
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Check your solution by first checking the end point , in the related equation. Pick a value greater than , such as 2, to check in the inequality. Solve for x. Divide both sides by 3 to isolate the variable.

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