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hoa [83]
4 years ago
11

What two numbers add to be 6 and multiply to be 15

Mathematics
1 answer:
yarga [219]4 years ago
4 0
   
\displaystyle \bf \\
x_1+x_2=6\\\\
x_1\cdot x_2=15\\\\
\Longrightarrow~~x^2-6x+15=0\\\\
x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{6\pm\sqrt{36-60}}{2}=\\\\
=\frac{6\pm\sqrt{-24}}{2}=\frac{6\pm2\sqrt{-6} }{2}=3\pm i\sqrt{6}\\\\
x_1=\boxed{3-i\sqrt{6}}\\\\
x_2=\boxed{3+i\sqrt{6}}\\\\
\texttt{Verify:}\\\\
x_1+x_2=3-\underline{i\sqrt{6}}+3+\underline{i\sqrt{6}}=3+3=6~~correct\\\\
x_1\cdot x_2=(3-i\sqrt{6})(3+i\sqrt{6})=3^2-(i\sqrt{6})^2=9+6=15~~correct



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For table D: Rate = (2 - 1.5)/(4 - 3) = 0.5/1 = 0.5

Therefore, the correct answer is option C.

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VMariaS [17]

Answer:the length of each side of the larger square is 6 centimeters.

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The area of the large square is y^2

The combined area of two squares is 45 square centimeters. This means that

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Each side of one square is twice as long as a side of the other square. This means that

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Substituting y = 2x into equation 1, it becomes

x^2 + (2x)^2 = 45

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3 years ago
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Ganezh [65]

Answer:

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After we solve this, we have

ax + by + cz + d = 0

In this problem, we have that:

(x_{0}, y_{0}, z_{0}) = (-5,-1,2)

(a,b,c) = (−1,−5,2)

So

a(x - x_{0}) + b(y - y_{0}) + c(z - z_{0}) = 0

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Multplying everything by -1

x + 5y - 2z + 14 = 0

3 0
3 years ago
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