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mezya [45]
2 years ago
13

2

Mathematics
1 answer:
Troyanec [42]2 years ago
7 0
The answer is 4

Since 3.3x 4 is 13.2 and plus 3.0 is 16.2
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[Angles question]
11111nata11111 [884]
Here is my friendly solution i'll skip the proof part for now. I am working on the others.

8 0
3 years ago
A 54-degree angle is bisected by a ray. What is the measure of each angle formed? Show all work.
Anarel [89]
For the answer to the question above asking What is the measure of each angle formed if A 54-degree angle is bisected by a ray?
well bisect means to divide by 2 
<span>so obviously if 54 is bisected it gives </span>
<span>54/2=27
</span>i hope this helps
7 0
3 years ago
Please answer this asap and please show work.
lesya692 [45]
So it is C because when you use rise over run, then you just look at the line were the line crosses trough the caskets and then you see that rise is 1 and run is two so it is 1/2 but if you convert the fraction into a decimal, the. It will be 0.5. The b is we’re the line goes trough the y-axis. So y=1/2+4 but you have to convort it into a decimal and it will be C y=0.5x+4. You welcome
7 0
2 years ago
PLEASE HELPPPPPPP
Fed [463]

Answer:

Molar mass = 254.60g/mol

Step-by-step explanation:

Mass = 8.02g

Volume = 812mL = 0.812L

Pressure (P) = 0.967atm

Temperature of the gas = 30°C = (30 + 273.15)K = 303.15K

Molecular weight = ?

To solve this question, we'll have to use ideal gas equation, PV = nRT

P = pressure of the gas

V = volume of the gas

n = number of moles of the gas

R = ideal gas constant = 0.082J/mol.K

T = temperature of the gas

PV = nRT

n = PV / RT

n = (0.967 * 0.812) / (0.082 * 303.15)

n = 0.7852 / 24.8583

n = 0.0315 moles

Number of moles = mass / molarmass

Molarmass = mass / number of moles

Molar mass = 8.02 / 0.0315

Molar mass = 254.60g/mol

The molar mass of the gas is 254.60g/mol

3 0
3 years ago
Please solve all of these, 50 points and I will be marking it brainliest, no links, they will be reported.​
Gwar [14]

Step-by-step explanation:

this is too

I need to use paper please

5 0
3 years ago
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