2

. Let X and Y be random variables of possible percent returns (0%, 10%,

bazaltina [42]

(a) The marginal distribution of X is

Pr(X = x) = ∑ Pr(X = x, Y = y)

… = 0.0625 + 0.0625 + 0.0625 + 0.0625

… = 0.25

That is, the first equality follows from the law of total probability, with the sum taken over y from {0, 5, 10, 15}. Each probability Pr(X = x, Y = y) is given in the table to be 0.0625.

Similarly, the marginal distribution of Y is

Pr(Y = y) = 0.25

(b) Yes, they're independent because

Pr(X = x, Y = y) = 0.0625,

and

Pr(X = x) Pr(Y = y) = 0.25 • 0.25 = 0.0625.

(c) The mean of X is

E[X] = ∑ x Pr(X = x)

… = 0.25 ∑ x

… = 0.25 (0 + 5 + 10 + 15)

… = 7.5

and you would find the same mean for Y,

E[Y] = 7.5

The variance of X is

V[X] = E[X^2] - E[X]^2

… = (∑ x^2 Pr(X = x)) - 7.5^2

… = 0.25 (∑ x^2) - 56.25

… = 0.25 (0^2 + 5^2 + 10^2 + 15^2) - 56.25

… = 31.25

and similarly,

V[Y] = 31.25

(each sum is taken with x and y from {0, 5, 10, 15})

7 0

3 years ago

kate buys 10 ticket to show. She also pays a 5$ parking fee. she spent $35 to see the show. What equation is this

Over [174]

Answer:

35 = 5 + 10x

Step-by-step explanation:

x = the ticket price.

Each ticket was $3

hope this helps :)

5 0

3 years ago

Read 2 more answers

لیست داده و

choli [55]

Given parameters:

Cost price of the article = Nu.28.30

Selling price of the article = Nu.29.30

Unknown:

Gain percentage = ?

The gain percentage is the same as the percentage profit on a trade.

The formula is given as:

Gain percentage = $\frac{Profit}{Cost price} x 100$

Profit = Selling price - Cost price

= Nu.29.30 - Nu.28.30

= Nu. 1

Now input the parameters and solve;

Gain percentage = $\frac{1}{28.3} x 100$

= 3.5%

The gain percent is 3.5%

3 0

3 years ago

Solve the given initial-value problem. y'' + 9y = 0, y(0) = 6, y'(0) = −3

Taya2010 [7]

I believe it's y'(0)=-3

I was only able to simplify the equation.

Hope this helps

5 0

3 years ago

Suppose that the cost of producing x tablets is defined by c(x)= 200 + 10x + 0.2x squared* where x represents the number if tabl

sammy [17]

we are given

$C(x)=200+10x+0.2x^2$

part-A:

Since, x is number of tablets

C(x) is cost of producing x tablets

so, vertical box is C(x)

so, we write in vertical box is "cost of producing x tablets"

Horizontal box is x

so, we write in horizontal box is "number of tablets"

part-B:

we have to find average on [a,b]

we can use formula

$\frac{C(b)-C(a)}{b-a}$

we are given point as

a: (15 , 395)

a=15 and C(15)=395

b: (20, 480)

b=20 , C(20)=480

now, we can plug values

$=\frac{480-395}{20-15}$

$=17$ ...........Answer

part-c:

we have to find average on [b,c]

we can use formula

$\frac{C(c)-C(b)}{c-b}$

we are given point as

b: (20, 480)

b=20 , C(20)=480

c:(25,575)

c=25 , C(c)=575

now, we can plug values

$=\frac{575-480}{25-20}$

$=19$ ..............Answer

5 0

4 years ago