Answer:x³-8x²-x+8
Step-by-step explanation:
x are equal to -1,1,8 respectively
to form the polynomials just simply use this method put (x-)to the given numbers that are zeros of the polynomials
(x-(-))(x-1)(x-8)
(x+1)(x-1)(x-8) →(x+1)(x-1) are diff. of two squares (x²-1)
(x²-1)(x-8)
x²(x-8)-1(x-8)
p(x)=x³-8x²-x+8
Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:
We are given the following in the question:
The numbers of teams remaining in each round follows a geometric sequence.
Let a be the first the of the geometric sequence and r be the common ration.
The
term of geometric sequence is given by:


Dividing the two equations, we get,

the first term can be calculated as:

Thus, the required geometric sequence is

102, 112, 120-129, 132, 142, 152, 162, 172, 182, 192, 200-299, 302, 312, 320-329, 332, 342, 352, 362, 372, 382, 392
2+10+7+100+2+10+7
138 integers.
Answer:
C.
Explanation: I guest it is base on my research but i dont have a solution peace