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3 years ago

Consider the quadratic function f(x)=2x^2-8x-10

Mathematics

1 answer:

Slav-nsk [51]3 years ago

6 0

Answer:

f(x) = 2x² - 8x - 10.

This is a parabola open upward (since a>0) with an axis of symmetry = -b/2a:

a) axis of symmetry: x = -(-8)/(2*2) = 8/4 = 2. Then x = 2, which is the x component of the vertex

b) for x = 2, f(x) = f(2) = - 18 (component of y of the vertex)

c) VERTEX(2, - 18)

d) DISCRIMINENT: b² - 4.a.c = 64 - 4*2*(-10) = 144

Hope this helps! :)

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2.14x - 42.9 for x = 22.4 ? A. -18.36 B. 5.026 C. 47.939 D. 90.839

Fynjy0 [20]

Answer:

Step-by-step explanation:

Your answer would be B., because you would multiply

2.14 x 22.4 =

47.939

then you will subtract that by 42.9

47.939 - 42.9 =

5.026

7 0

4 years ago

Give examples of a 100% increase, 100% decrease, and 100% error. Explain each.

lakkis [162]

Answer:

100% increase from 100 is 200, the difference is 100.

100% decrease from 100 is 0, the difference is -100

error means that you were quite a long way off from the true value.

4 0

3 years ago

a)Convert 7.5 cm into m b) convert 2 m into mm c) Convert 5 m into cm d) convert mg into 9 e)Convert 1.5 mg into kg f)convert 1

dem82 [27]

Answer:

0.075 metre

2000 mm

500 cm

0.001 gram

1.5 × 10-6 kilogram

86400 second

18000 second

Step-by-step explanation:

hope it helps

7 0

3 years ago

Reggy is a reading a 340 page book. It takes him 7 days to read the first 119 pages. At this rate, how much longer will it take

julsineya [31]

Answer:

Step-by-step explanation:

If he reads 119 pgs in 7 days that mean 119/7 = 17 he reads 17 pgs per day

next 340-119 = 221 then 221/17= 13

5 0

3 years ago

A certain large manufacturing facility produces 20,000 parts each week. The manager of the facility estimates that about 1% of t

Slav-nsk [51]

Answer:

198 is the variance for the number of defective parts made each week.

Step-by-step explanation:

We are given the following in the question:

Number of parts produced each week = 20,000

Percentage of defective parts = 1%

We have to calculate the variance for the number of defective parts made each week.

We treat defective part as a success.

P(Defective part) = 1% = 0.01

$p = 0.01$

Then the number defective parts follows a binomial distribution .

Formula for variance =

$\sigma^2 = np(1-p) = 20000(0.01)(1-0.01) = 198$

Thus, 198 is the variance for the number of defective parts made each week.

8 0

4 years ago