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Troyanec [42]
3 years ago
6

Write the equation of the line perpendicular to y= 2x +1 that passes through the point (6,2)

Mathematics
1 answer:
Xelga [282]3 years ago
6 0

Answer:

Step-by-step explanation:

Hello:

the equation is : y = ax+b

the slope is a : a×(2) = -1......( perpendicular to a line with a slope of 2 for : y=2x+1)

a =-1/2          y=(-1/2)x+b

the line that passes through (6, 2) : 2 = (-1/2)(6)+b

b = 5

the equation is :  y  = (-1/2)x+5

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Using the transformation T: (x, y) (x + 2, y + 1), find the distance named. Find the distance BB'
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Answer:

\sqrt{5}\ units


Step-by-step explanation:

we know that

The rule of the translation is equal to

(x,y)-----> (x+2,y+1)

That means

The translations is 2 units to the right and 1 unit up

Let

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the formula to calculate the distance between two points is equal to


d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}


substitute

d=\sqrt{((y+1)-y)^{2}+((x+2)-x)^{2}}


d=\sqrt{(1)^{2}+(2)^{2}}


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