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gulaghasi [49]
2 years ago
14

WHAT IS THE LENGTH!!!

Mathematics
1 answer:
Murljashka [212]2 years ago
6 0

The figure is a trapezoid (or trapezium), and the exact length of the trapezoid is 5 units

<h3>How to determine the length?</h3>

The figure is a trapezoid with the following parameters:

Area = 107.95

Base= 12

Height = 12.7

Length = x

The area of a trapezoid is:

Area = 0.5 * (Base + Length) * Height

So, we have:

0.5 * (12 + Length) * 12.7 = 107.95

Evaluate the product

(12 + Length) * 6.35 = 107.95

Divide both sides by 6.35

12 + Length = 17

Subtract 12 from both sides

Length =  5

Hence, the length of the trapezoid is 5 units

Read more about areas at:

brainly.com/question/24487155

#SPJ1

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A homeowner has a mortgage payment of $998.60, an annual property tax bill of $590, and an annual fire insurance premium of $280
grandymaker [24]

Answer:

the monthly payment is $134.72

Step-by-step explanation:

This is if the mortgage is annual also.

add all 3 which would equal 1,616.6.

But "why?" you ask is it so expensive.

it is still annual so divide it by 12 and you have 134.72

8 0
3 years ago
Snow White has 30 apples . She gave 6 apples to the prince and 21 apples to her seven dwarfs. Find the percentage of apples Snow
motikmotik
She has 3 apples left
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3 years ago
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3 questions in 1
MrRissso [65]

Answer:

1. D. 20, 30, and 50

2. A. 86

3. B. 94

Step-by-step explanation:

1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.

The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.

Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.

Thus:

Q1 = (85 + 87)/2 = 86

Q3 = (93 + 95)/2 = 94

IQR = Q3 - Q1 = 94 - 86

IQR = 8

Outliers in the data set are data values below the lower limit or above the upper limit.

Let's find the lower and upper limit.

Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74

The data values below the lower limit (74) are 20, 30, and 50

Let's see if we have any data value above the upper limit.

Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106

No data value is above 106.

Therefore, the only outliers of the data set are:

D. 20, 30, and 50

2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.

Thus:

Q1 = (85 + 87)/2 = 86

3. Q3 = (93 + 95)/2 = 94

3 0
2 years ago
Tyler does squats and pushups. He wants to increase the number of each type of exercise by 20% by the end of the month. He curre
Semenov [28]

Answer:

Tyler currently does 40 squats

Step-by-step explanation:

Tyler does squats and pushups.

<u>Currently:</u>

Number of pushups = 25

Number of squats = x

Total number = 25 + x

<u>After increase:</u>

Number of pishups =25\cdot (1+0.2)=1.2\cdot 25=30

Number of squats =x\cdot (1+0.2)=1.2x

Total number =30+1.2x

If Tyler meets his goal, he will do a total of 13 more squats and pushups than he does now, thus

(30+1.2x)-(25+x)=13\\ \\30+1.2x-25-x=13\\ \\1.2x-x=13-30+25\\ \\0.2x=8\\ \\2x=80\\ \\x=40

6 0
3 years ago
Find all real zeros of 4x^3-20x+16
Pani-rosa [81]

Answer:

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Step-by-step explanation:

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It can also be informative to add the coefficients in both cases--as is, and with the odd-degree term signs changed. Here, the sum is zero in the first case, so we know immediately that x=1 is a zero of the expression. That is sufficient to help us reduce the problem to finding the zeros of the remaining quadratic factor.

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  x = (-1 ±√17)2

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The graph shows the zeros of the expression. It also shows the quadratic after dividing out the factor (x-1). The vertex of that quadratic can be used to find the remaining solutions exactly: -0.5 ± √4.25.

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3 years ago
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