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Mrac [35]
3 years ago
15

Determine the area of the given rhombus. ANSWERS: 140 square units 35 square units 70 square units 17.5 square units

Mathematics
1 answer:
sergey [27]3 years ago
7 0

Answer:

17.5

Step-by-step explanation:

A = \frac{pq}{2}

p = 7

q = 5

7 x 5 = 35

35 ÷ 2 = 17.5

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PIT_PIT [208]
This question still doesn't make any sense, unfortunately.
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4 years ago
5 A classroom has 42 desks. Each row has 7 seats. Write an equation to find the number of rows in the classroom. Solve the equat
aliya0001 [1]

Answer:

42 / 7 = 6

Step-by-step explanation:

There are 6 rows in the class room.

4 0
3 years ago
Read 2 more answers
What is the equation of the line that passes through the point (-4, 2) and has a<br> slope of -2?
Furkat [3]

Step-by-step explanation:

use the equation of the straight line

y-y1=m (x-x1)

y-2=-2(x+4)

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I hope this helps

4 0
3 years ago
Bastien, Inc. has been manufacturing small automobiles that have averaged 50 miles per gallon of gasoline in highway driving. Th
alexira [117]

Answer:

We conclude that the the manufacturer's advertising campaign is not correct.

P-value of test = 0.067.

Step-by-step explanation:

We are given that an independent testing service road-tested 36 of the automobiles. The sample showed an average of 51.5 miles per gallon. The population standard deviation is 6 miles per gallon.

We have to conduct a test to determine whether or not the manufacturer's advertising campaign is legitimate.

<u><em>Let </em></u>\mu<u><em> = population average gasoline of new small cars in highway driving.</em></u>

SO, <u>Null Hypothesis</u>, H_0 : \mu \leq 50 miles per gallon   {means that the manufacturer's advertising campaign is not correct}

<u>Alternate Hypothesis</u>, H_A : \mu > 50 miles per gallon   {means that the manufacturer's advertising campaign is correct}

The test statistics that will be used here is <u>One-sample z test</u> <u>statistics</u> as we know about the population standard deviation;

                         T.S.  = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where,  \bar X = sample average gasoline = 51.5 miles per gallon

              \sigma = population standard deviation = 6 miles per gallon

              n = sample of automobiles = 36

So, <em><u>test statistics</u></em>  =   \frac{51.5-50}{\frac{6}{\sqrt{36} } }

                               =  1.50

<em>Now at 0.05 significance level, the z table gives critical value of 1.6449 for right-tailed test. Since our test statistics is less than the critical values of z as 1.50 < 1.6449, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.</em>

<u>Also, P-value is given by the following formula;</u>

         P-value = P(Z > 1.50) = 1 - P(Z \leq 1.50)

                                            = 1 - 0.93319 = <u>0.067 or 6.7%</u>

Therefore, we conclude that the the manufacturer's advertising campaign is not correct as its new small cars average less than or equal to 50 miles per gallon in highway driving.

3 0
4 years ago
Need help on this please and thank you
larisa [96]

Step-by-step explanation:

a. 4/7t =56

4t= 392

t=98

b. 4=1/2 b -12

4+12=1/2 b

16=1/2 b

so, b =32

4 0
3 years ago
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