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Mrac [35]
3 years ago
15

Determine the area of the given rhombus. ANSWERS: 140 square units 35 square units 70 square units 17.5 square units

Mathematics
1 answer:
sergey [27]3 years ago
7 0

Answer:

17.5

Step-by-step explanation:

A = \frac{pq}{2}

p = 7

q = 5

7 x 5 = 35

35 ÷ 2 = 17.5

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13-5m=4-6m show work please
Vesna [10]
First subtract 4 from both sides
13 - 4 - 5m = - 6m

then simplify
9 - 5m = - 6m

add -5 to both sides
9 = - m

since a variable shouldn't be negative the answer should be
m = - 9

(I prefer having the variable on the left side)
4 0
2 years ago
Is it scaling isosceles or equilateral and what is the answer
garik1379 [7]

Answer:

scalene

Step-by-step explanation:

\textsf{Sum of internal angles;}

  71+50+6x-1=180

 6x-1=180-71-50

  6x-1=59

6 0
2 years ago
Read 2 more answers
A set of points in the xy-coordinate plane meets two conditions, as described.
Pepsi [2]

Answer:

Condition 1:   y>0

Condition 2:  x+y>-2

Step-by-step explanation:

We are told that we have a set of points in the Cartesian system (i.e. x-y coordinate), so we can define our point as:

(x,y)

We are given two conditions and we want to create a system of inequalities. Now, generally speaking, inequalities are expressions relating mathematical expressions through 'comparison' (i.e. less than, greater than, or less/greater and equal to) usually recognized by , >, \leq and \geq, respectively.

So in our case let set up our inequalities.

Condition 1: the y-coordinate is positive

This can be mathematically translated as

y>0

(i.e. y is greater than 0, therefore positive)

Condition 2: the sum of the coordinates is more than -2

This can be mathematically translated as

x+y>-2

(i.e. the summation of the two coordinates is greater than -2 but not equal to).

The system of inequalities described by the two conditions is:

y>0\\x+y>-2

3 0
3 years ago
Find the area of A rectangle with a length of 3 inches and a width of 1/8 inch
n200080 [17]
Area= length * width
Therefore, you do 3*1/8
ie 3/8

idk if its right  :/
7 0
3 years ago
Consider the graph of the quadratic function y = 3x2 – 3x – 6. What are the solutions of the quadratic equation 0 = 3x2 − 3x − 6
son4ous [18]
Y = 3x^2 - 3x - 6 {the x^2 (x squared) makes it a quadratic formula, and I'm assuming this is what you meant...}

This is derived from:
y = ax^2 + bx + c

So, by using the 'sum and product' rule:

a × c = 3 × (-6) = -18

b = -3

Now, we find the 'sum' and the 'product' of these two numbers, where b is the 'sum' and a × c is the 'product':

The two numbers are: -6 and 3

Proof:

-6 × 3 = -18 {product}

-6 + 3 = -3 {sum}

Now, since a > 1, we divide a from the results

-6/a = -6/3 = -2

3/a = 3/3 = 1

We then implement these numbers into our equation:

(x - 2) × (x + 1) = 0 {derived from 3x^2 - 3x - 6 = 0}

To find x, we make x the subject of 0:

x - 2 = 0

OR

x + 1 = 0

Therefore:

x = 2

OR

x = -1

So the x-intercepts of the quadratic formula (or solutions to equation 3x^2 - 3x -6 = 0, to put it into your words) are 2 and -1.


We can check this by substituting the values for x:

Let's start with x = 2:

y = 3(2)^2 - 3(2) - 6
= 3(4) - 6 - 6
= 12 - 6 - 6
= 0 {so when x = 2, y = 0, which is correct}

For when x = -1:

y = 3(-1)^2 - 3(-1) - 6
= 3(1) + 3 - 6
= 3 + 3 - 6
= 0 {so when x = -1, y = 0, which is correct}
7 0
3 years ago
Read 2 more answers
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