28. bacteria and fungi.
29. answer 3
30. answer 2
Answer:
15.21 %
Explanation:
If we recall the basic formula of Hardy-Weinberg's equilibrium ; we have the following below:
p + q = 1
p² + 2pq + q² = 1
where;
p = frequency of the dominant allele in the population
q = frequency of the recessive allele in the population
p² = percentage of homozygous dominant individuals
q² = percentage of homozygous recessive individuals
2pq = percentage of heterozygous individuals
Given that p= 0.68 and q = 0.39
the percentage of the homozygous recessive genotype (q² ) will be
(0.39)² = 0.1521
= 0.1521 × 100
= 15.21 %
∴ the percentage of the population that has a homozygous recessive genotype = 15.21 %
Oviparity is a mode of reproduction in which young, developed in fertilized eggs, laid outside the mother's body. This mode of reproduction is found in most reptiles and all birds.
Viviparity means that their young develop inside the mother's body and are born alive. This is the mode of most mammals.
<span>Ovoviviparity is similar to viviparity in that there is internal fertilization and the young ones are born alive but differ in that there is no placental connection, the young are fed by egg yolk. This is found i</span><span>n </span><span>seahorses, for example.</span>
