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kotykmax [81]
2 years ago
12

Why is it now difficult for computer technology to maintain the pace of

Computers and Technology
1 answer:
KatRina [158]2 years ago
6 0

It now difficult for computer technology as manufacturing cannot keep up with overwhelming transistor demand.

<h3>What was Moore's Law ?</h3>

Moore's Law is the one that talks about the fact that the number of transistors on a microchip is one that often goes up about two years always, even if the cost of computers is reduced.

Based on the above, It now difficult for computer technology as manufacturing cannot keep up with overwhelming transistor demand.

Learn more about computer technology  from

brainly.com/question/24912812

#SPJ1

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The term "resolution" refers to ______.
Usimov [2.4K]

Options A and C can get you confused. We can choose option A if our argument is based entirely on digital images. The correct answer, however, is  C: Number of pixels you see on your computer monitor.

Resolution describes the clarity and sharpness of a picture that can be measured by the number of pixels contained on a display monitor. It can be expressed by the number of horizontal (width) and vertical pixels (height) represented by a screen. The clarity and sharpness are always dependent on the resolution and size of the monitor.

4 0
3 years ago
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Answer:

g

Explanation:

4 0
2 years ago
A communication sent through Transmission Control Protocol (TCP) arrives out of order. What allows the data to be put back toget
algol13

Answer:

Error detection.

Explanation:

Tcp is a transport layer protocol. It is said to be connection oriented because it requires a handshake or established connection between the sender and the receiver.

Once a handshake is made, the segments of the packets are sent across and the connection is closed.

The error detection does not only carry out integrity checks, but allows for sequence numbering from the sender to receiver. If the packets arrives out of order, the sequence numbers are used to arrange them in the correct order.

5 0
3 years ago
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I've seen this problem before, you just need the solution to the 'while' loop, right?


Assuming your variable names are the same as the generic question your while loop should look like this:


while (keepGoing != 'n')

7 0
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