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kotykmax [81]
2 years ago
12

Why is it now difficult for computer technology to maintain the pace of

Computers and Technology
1 answer:
KatRina [158]2 years ago
6 0

It now difficult for computer technology as manufacturing cannot keep up with overwhelming transistor demand.

<h3>What was Moore's Law ?</h3>

Moore's Law is the one that talks about the fact that the number of transistors on a microchip is one that often goes up about two years always, even if the cost of computers is reduced.

Based on the above, It now difficult for computer technology as manufacturing cannot keep up with overwhelming transistor demand.

Learn more about computer technology  from

brainly.com/question/24912812

#SPJ1

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White hat hackers use their capabilities to uncover security failings to help safeguard organizations from dangerous hackers. They can sometimes be paid employees or contractors working for companies as security specialists who attempt to find gaps in security.
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Complete the do-while loop to output every number form 0 to countLimit using printVal. Assume the user will only input a positiv
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Answer:

PART ONE

  1. import java.util.Scanner;
  2. public class CountToLimit {
  3.    public static void main(String[] args) {
  4.        Scanner scnr = new Scanner(System.in);
  5.        int countLimit = 0;
  6.        int printVal = 0;
  7.        // Get user input
  8.        System.out.println("Enter Count Limit");
  9.        countLimit = scnr.nextInt();
  10.        do {
  11.            System.out.print(printVal + " ");
  12.            printVal = printVal + 1;
  13.        } while ( printVal<=countLimit );
  14.        System.out.println("");
  15.        return;
  16.    }
  17. }

PART TWO

  1. import java.util.Scanner;
  2. public class NumberPrompt {
  3.    public static void main (String [] args) {
  4.        Scanner scnr = new Scanner(System.in);
  5.        System.out.print("Your number < 100: ");
  6.       int  userInput = scnr.nextInt();
  7.      do {
  8.           System.out.print("Your number < 100: ");
  9.           userInput = scnr.nextInt();
  10.       }while (userInput>=100);
  11.        System.out.println("Your number < 100 is: " + userInput);
  12.        return;
  13.    }
  14. }

Explanation:

In Part one of the question, The condition for the do...while loop had to be stated this is stated on line 14

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