Need help solving this

An average of 145 people visited a 4-day exhibition on the first 3 days. Another 205 people visited the exhibition on the fourth

Alenkinab [10]

Answer:

160 visitors.

Step-by-step explanation:

Given:

An average of 145 people visited a 4-day exhibition on the first 3 days, <u>means here average people visited in 3 days is given 145.</u>

Average = 145

Number of people, n = 3

Another 205 people visited the exhibition on the fourth day.

To find:

What is the average number of visitors per day ?

Solution:

<u>First of all we will find total number of people visited in 3 days:-</u>

As we know:

$Average=\frac{Sum\ of\ observation}{number\ of\ observation}$

$145=\frac{Sum\ of\ observation}{3}\\$

Multiplying both sides by 3

$145\times3=\frac{Sum\ of\ observation}{3}\times3\\435=Sum\ of\ observations$

Thus, we found that total number of people visited in 3 days is 435 and as 205 people visited in fourth day, then total number of people increased to

435 + 205 = 640

Now, sum of total observations( total number of people ) = 640

And number of observation ( number of days ) = 4

Now, we will calculate average number of visitors visit per day :-

$Average=\frac{Sum\ of\ observation}{number\ of\ observation}$

$=\frac{640}{4} \\=160\ visitors$

Thus, the average number of visitors per day is 160 visitors.

6 0

3 years ago

If 3ax+b+c, then x equals?

Viktor [21]

This is not an Equation! this is an Sentence in Al Jebra!
but you means : if 3ax+b=c, then x =?
3ax=c-bX = $x= \frac{c-b}{3a}$

5 0

3 years ago

the angle theta is in the second quadrant and cos theta = -2/√29 determine possible coordinates for point P on the terminal arm

Gekata [30.6K]

$\cos(\theta)=-\frac{2}{\sqrt{29}}$ and $\theta$ lies in $2^{\text{th}}$ quadrant.

where, $x-$ coordinate is negative, and $y-$ coordinate is positive

so it can't a.

now, cosine means, side adjacent over the hypotenuse, in Cartesian plane, that will be $x-$ coordinate over the distance from origin.

Assume the triangle , with base $2$ units and hypotenuse $\sqrt{29}$ and it's in second quadrant. (so $\cos(\theta)=-\frac{2}{\sqrt{29}}$ )

now, the leftmost point on $x-$ axis is , obviously $(-2,0)$

and by Pythagoras theorem, we can find the perpendicular side, that will be $y^2=(\sqrt{29})^2-(2)^2\implies y=5$

so the coordinates of the upper vertex is $(-2,5)$, each point lying on this "ray" should have equal ratio of respective coordinates. i.e. $\frac25=\left|\frac xy\right| $

and it should lie on second quadrant, so $x<0 \, y>0$

Option d satisfies this.

6 0

3 years ago

Sovle for x. 2x + 6 = - r - 15

Igoryamba

Answer:

$x = \frac{-r - 21}{2}$

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Remember to do the opposite of PEMDAS.

PEMDAS =

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

First, subtract 6 from both sides:

2x + 6 (-6) = -r - 15 (-6)

2x = -r + (-15 - 6)

2x = -r + (-21)

2x = - r - 21

Next, divide 2 from both sides:

$\frac{2x}{2} = \frac{-r - 21}{2}$

$x = \frac{-r - 21}{2}$

~

6 0

3 years ago

About 13 out of 20 homes have a personal computer at On a STREET with 60 homes how many would you expect to have a personal comp

kirza4 [7]

39

So 13-20 Is 26-40 Which makes 49-60

3 0

3 years ago