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Alex73 [517]
2 years ago
15

I need help please ):

Mathematics
1 answer:
ANTONII [103]2 years ago
4 0

Answer: yeeet

Step-by-step explanation:

dap

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Serika has hired Tom to build her a dollhouse. The dollhouse will be a scale model of her home, and the scale will be 2 inches :
sveticcg [70]

Answer:

96 square inches

Step-by-step explanation:

The scale is 2 inches : 3 feet

Thus for 18 feet in Serika's real house, the model is 18 * (2"/3') = 12 inches

For 12 feet in Serika's real house, the model is 12 * (2"/3') = 8 inches

Area of carpeting needed in Serika's dollhouse = 12" * 8" = 96 square inches

7 0
2 years ago
The interest on a $6,000, 6%, 60-day note receivable is
Musya8 [376]

Answer:

The answer is c or $180

Step-by-step explanation:

4 0
3 years ago
The table below represents a function. Which of the following equations could be its function rule?
worty [1.4K]

Answer:

y=2x-2 is the required equation.

Therefore, the second option is true.

Step-by-step explanation:

We know that the slope-intercept form of the line equation of a linear function is given by

y=mx+b

where m is the slope and b is the y-intercept

Taking two points (0, -2) and (1, 0) from the table to determine the slope using the formula

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(0,\:-2\right),\:\left(x_2,\:y_2\right)=\left(1,\:0\right)

m=\frac{0-\left(-2\right)}{1-0}

m=2

substituting the point (0, -2) and the slope m=2 in the slope-intercept form to determine the y-intercept i.e. 'b'.

y=mx+b

-2 = 2(0)+b

-2=0+b

b=-2

Now, substituting the values of m=2 and b=-2 in the slope-intercept form to determine the equation of a linear function

y=mx+b

y=2x+(-2)

y=2x-2

Thus, y=2x-2 is the required equation.

Therefore, the second option is true.

3 0
2 years ago
Write one sine and one cosine equation for each graph below.
pychu [463]

Answer:

Q13. y = sin(2x – π/2); y = - 2cos2x  

Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1

Step-by-step explanation:

Question 13

(A) Sine function

y = a sin[b(x - h)] + k

y = a sin(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Phase shift = π/2.  

2h =π/2

h = π/4

The equation is

y = sin[2(x – π/4)} or

y = sin(2x – π/2)

B. Cosine function

y = a cos[b(x - h)] + k

y = a cos(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Reflected across x-axis, y ⟶ -y

The equation is y = - 2cos2x  

Question 14

(A) Sine function

(1) Amp = 2; a = 2

(2) Shifted down 1; k = -1

(3) Per = π; b = 2

(4) Phase shift = 0; h = 0

The equation is y = 2sin2x -1

(B) Cosine function

a = 2, b = -1; b = 2

Phase shift = π/2; h = π/4

The equation is

y = -2cos[2(x – π/4)] – 1 or

y = -2cos(2x – π/2) - 1

6 0
2 years ago
Solve the system of inequalities:<br> 6y≥42<br> 4y+12≤0
Hatshy [7]

Answer:

no solution

Step-by-step explanation:

6y≥42

Divide each side by 6

6y/6≥42/6

y≥7

Then solve the second one

4y+12≤0

Subtract 12 from each side

4y+12-12≤0-12

4y ≤-12

Divide each side by 4

4y/4 ≤-12/4

y ≤-3

There is no solution since there is no overlap

8 0
2 years ago
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