Polynomials are mathematical expressions involving variables raised with non-negative integers and coefficients. The polynomial whose factors are (a²-6) and (a²+4) is a⁴ - 2a² - 24.
<h3>What is a polynomial?</h3>
Polynomials are mathematical expressions involving variables raised with non-negative integers and coefficients(constants who are in multiplication with those variables) and constants with only operations of addition, subtraction, multiplication and non-negative exponentiation of variables involved.
Example: x²+3x+5 is a polynomial.
The polynomial whose factors are (a²-6) and (a²+4) is,
P(x) = (a²-6)(a²+4)
= a⁴ + 4a² - 6a² - 24
= a⁴ - 2a² - 24
Hence, The polynomial whose factors are (a²-6) and (a²+4) is a⁴ - 2a² - 24.
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Answer:

where x₁ and x₂ are values in the interval [x,y] respectively
Step-by-step explanation:
Well, first to determine the average rate of change of a function, you should have the interval of the values of x for the function.
So lets assume you have a function;

And the interval as [1,3]
Then the average rate of change for the function f(x) will be;

where x₁ and x₂ are the interval coordinates x,y respectively. In this case x₁=1 and x₂=3
To find the average rate of change in this example will be;

Answer:
Step-by-step explanation:
Answer:
Data
Equation 25x² + 64y² = 1600
Process
1.- Divide all the equation by 1600
25x²/1600 + 64y²/ 1600 = 1600/1600
-Simplify
x²/64 + y²/ 25 = 1
2.- Equation of a horizontal ellipse
3.- Find a, b and c
a² = 64 a = 8
b² = 25 b = 5
-Calculate c with the Pythagorean theorem
a² = b² + c²
-Solve for c
c² = a² - b²
-Substitution
c² = 8² - 5²
-Simplification
c² = 64 - 25
c² = 39
-Result
c = √13
4.- Find the center
C = (0, 0)
5.- Find the vertices
V1 = (-8, 0) V2 = (8, 0)
6.- Find the foci
F1 = (-√13, 0) F2 = (√13, 0)
Answer:
a) integral = 24.72
b) |Error| ≤ 0.4267
Step-by-step explanation:
a)
The integral:

can be approximated with the midpoint rule, as follows:
6.7*(0.8 - 0.0) + 8.9*(1.6 - 0.8) + 6.9*(2.4-1.6) + 8.4*(3.2 - 2.4) = 24.72
(that is, all the intervals are 0.8 units length and f(x) is evaluated in the midpoint of the interval)
b)The error bound for the midpoint rule with <em>n</em> points is:
|Error| ≤ K*(b - a)^3/(24*n^2)
where <em>b</em> and are the limits of integration of the integral and K = max |f''(x)|
Given that -5 ≤ f''(x) ≤ 1, then K = 5. Replacing into the equation:
|Error| ≤ 5*(3.2 - 0)^3/(24*4^2) = 0.4267