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2 years ago

Find the inverse of {(-2, 4), (-3, -1), (2, 2), (3, 4)}. State whether the inverse is a function.

Mathematics

1 answer:

Flura [38]2 years ago

8 0

Answer:

(-4, 2), (-1, -3), (2,0), (4,3).

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A sequence is defined recursively by the formula f(n + 1) = f(n) + 3 . The first term of the sequence is –4. What is the next te

sergiy2304 [10]

Translate the equation to math.
It says the term after the current term is the current term plus 3.
Next term = this term + 3
Next term = -4+3
The next term is then -4+3 or -1.

Answer= - 1

Hope this helps :)

7 0

3 years ago

A man and his three children spent $40 to attend a show. A second family of three children and their two parents spent $53 for t

wariber [46]

The cost for the children tickets is $9

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3 years ago

On the graph of f(x)=sinx and the interval [2π,4π), for what value of x does f(x) achieve a minimum?

lawyer [7]

Answer:

Step-by-step explanation:

The minimum value of sinx is -1 when x = 3π/2, 7π/2, ...

In [2π, 4π), x = 7π/2

8 0

2 years ago

Find the value of x. *<br> Please help I’m really confused

mezya [45]

Due to the Triangle Angle Sum Theorem, we know that the sum of the interior angles of a triangle is 180 degrees.

90 + 2x - 2 + x + 5 = 180 degrees.

Combine like terms.

3x + 93 = 180

Subtract 93 from both sides.

3x = 87

Divide both sides by 3

x = 29

4 0

3 years ago

(15 pts) 4. Find the solution of the following initial value problem: y"-10y'+25y = 0 with y(0) = 3 and y'(0) = 13

jolli1 [7]

Answer:

$y(x)=3e^{5x}-2xe^{5x}$

Step-by-step explanation:

The given differential equation is $y''-10y'+25y=0$

The characteristics equation is given by

$r^2-10r+25=0$

Finding the values of r

$r^2-5r-5r+25=0\\\\r(r-5)-5(r-5)=0\\\\(r-5)(r-5)=0\\\\r_{1,2}=5$

We got a repeated roots. Hence, the solution of the differential equation is given by

$y(x)=c_1e^{5x}+c_2xe^{5x}...(i)$

On differentiating, we get

$y'(x)=5c_1e^{5x}+5c_2xe^{5x}+c_2e^{5x}...(ii)$

Apply the initial condition y (0)= 3 in equation (i)

$3=c_1e^{0}+0\\\\c_1=3$

Now, apply the initial condition y' (0)= 13 in equation (ii)

$13=5(3)e^{0}+0+c_2e^{0}\\\\13=15+c_2\\\\c_2=-2$

Therefore, the solution of the differential equation is

$y(x)=3e^{5x}-2xe^{5x}$

5 0

3 years ago