If the equation is given in factored form and the roots are real, then you can identify the x-coordinate of the vertex by averaging the 2 root values. For example, if the roots are -2 and 5, the x-coord. of the vertex is (-2+5)/2, or 3/2.
Once you have this x value, subst. the value into the given equation to calculate y. Then write the vertex as (x,y).
Answer:
The expression is 10t = 65
Step-by-step explanation:
At the point where the local train and the express train meet, both trains would have travelled an equal distance.
A local train leaves the station in Springfield traveling toward New York City at a constant rate of 55 mph.
Let t represent the time it spent in travelling a given distance.
Distance = speed × time
Therefore,
Distance travelled by the local train is 55 × t = 55t
The express train headed for New York City on the same route leaves the station 1 hour later. The rate of the express train is 65 mph. It means that total time spent travelling the same distance as the local train is t - 1
Therefore, distance travelled is
65(t - 1)
Since the distance travelled is the same, therefore,
55t = 65t - 65
65t - 55t = 65
10t = 65
Answer:
communicative, you can remember this by saying (the rule for the communicative property, is as easy as can be, just remember a+b is the same as b+a )
Answer:
11
Step-by-step explanation:
Given: 
Using PEDMAS rule to solve it.
Now, simplifying:
We first open parenthesis which is (-7) = -7
= 
Now, we evaluate the exponent which is 
Next, we divide -36 by 12 to get -3
= 
Next, we multiply -2 and -7 to get 14
= 
Lastly, we add -3 and 14 to get 11
= 
∴ Answer is 11
Answer:
The distance reduces to 0 as you go from 0° to 90°
Step-by-step explanation:
The question requires you to find the distance using different values of L and check the trend of the values.
Given C=2×pi×r×cos L where L is the latitude in ° and r is the radius in miles then;
Taking r=3960 and L=0° ,
C=2×
×3960×cos 0°
C=2××3960×1
C=7380
Taking L=45° and r=3960 then;
C= 2××3960×cos 45°
C=5600.28
Taking L=60° and r=3960 then;
C=2××3960×cos 60°
C=3960
Taking L=90° and r=3960 then;
C=2××3960×cos 90°
C=2××3960×0
C=0
Conclusion
The values of the distance from around the Earth along a given latitude decreases with increase in the value of L when r is constant
