Your answer should be true
Roots of the polynomial are values of x when f(x)=0,so
to find the roots of the polynomial we need to solve the equation
x²+9x-70=0 , a=1, b=9,c=-70
![x= \frac{-b+/- \sqrt{ b^{2}-4ac } }{2a} ](https://tex.z-dn.net/?f=x%3D%20%5Cfrac%7B-b%2B%2F-%20%5Csqrt%7B%20b%5E%7B2%7D-4ac%20%7D%20%7D%7B2a%7D%0A%0A%0A)
Answer:
m = -4
Step-by-step explanation:
The answer is
![- \frac{1}{10}](https://tex.z-dn.net/?f=-%20%5Cfrac%7B1%7D%7B10%7D%20)
To figure this out, convert both numbers to fractions. 1.03 = 1
![\frac{3}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B100%7D%20)
and (-10.3) = -10
![\frac{3}{10}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B10%7D%20)
. Now, convert to improper fractions.
1
![\frac{3}{100} = [tex] \frac{103}{100}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B100%7D%20%20%3D%20%5Btex%5D%20%5Cfrac%7B103%7D%7B100%7D%20)
-10
![\frac{3}{10}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B10%7D%20)
=
![- \frac{103}{10}](https://tex.z-dn.net/?f=-%20%5Cfrac%7B103%7D%7B10%7D%20)
Now, divide. Dividing fractions is the same as multiplying by the reciporical. So:
![-\frac{103}{10} \ becomes\ \frac{10}{103}](https://tex.z-dn.net/?f=%20-%5Cfrac%7B103%7D%7B10%7D%20%20%5C%20becomes%5C%20%20%5Cfrac%7B10%7D%7B103%7D%20)