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2 years ago

Consider the cylinder below. Which statements are true?

Mathematics

1 answer:

JulijaS [17]2 years ago

4 0

Answer:

a and c is true

Step-by-step explanation:

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In ∆GHI and ∆JKL, GH = JK, HI = KL, GI = 9’, m∠H = 45°, and m∠K = 65°. Which of the following is not possible for JL: 5’, 9’ or

Aliun [14]

Answer:

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Step-by-step explanation:

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3 years ago

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Find the missing side lengths. All answers should be in fully simplified form. a=? b?

Alekssandra [29.7K]

Answer:

a=8 b=6

Step-by-step explanation:

Using the Pythagorean theorem, a^2+b^2=c^2, and in this case, a^2+b^2=10^2 = 100

so a^2+b^2=100

8^2+6^2=100

64+36=100 ✔

and since A is longer than B, a=8, b=6

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3 years ago

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Solve the equation using square roots.x2-14=-10

ElenaW [278]

Answer:

x=2

Step-by-step explanation:

$x^{2} -14=-10\\$

Add 14 to both sides

$x^{2}=4$

Square root it

x=2

8 0

3 years ago

Which polynomial, when added to the polynomial 5x^2–3x–9, is equivalent to: x^2–5x+6?

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Look at the attachment

8 0

3 years ago

3. Two cars are parked, 150m apart, and on opposite sides of a building. A camera on the top of the building rotates and can vie

allsm [11]

Answer:

The building is 61.5 m tall

Step-by-step explanation:

The image below is a diagram where all the given distances and angles are shown. We have additionally added some variables:

h = height of the building

a, b = internal angles of each triangle

x = base of each triangle

The angles a and b can be easily found by subtracting the given angles from 90° since they are complementary angles, thus:

a = 90° - 37° = 53°

b = 90° - 42° = 48°

Now we apply the tangent ratio on both triangles separately:

$\displaystyle \tan a=\frac{\text{opposite leg}}{\text{adjacent leg}}$

$\displaystyle \tan 53^\circ=\frac{150-x}{h}$

$\displaystyle \tan 48^\circ=\frac{x}{h}$

From the last equation:

$x=h.\tan 48^\circ$

Substituting into the first equation:

$\displaystyle \tan 53^\circ=\frac{150-h.\tan 48^\circ}{h}$

Operating on the right side:

$\displaystyle \tan 53^\circ=\frac{150}{h}-\tan 48^\circ$

Rearranging:

$\displaystyle \tan 53^\circ+\tan 48^\circ=\frac{150}{h}$

Solving for h:

$\displaystyle h=\frac{150}{\tan 53^\circ+\tan 48^\circ}$

Calculating:

h = 61.5 m

The building is 61.5 m tall

5 0

3 years ago