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scZoUnD [109]
3 years ago
10

Which line has a y-intercept of -2? A) L B) P C) T D) Both L and T

Mathematics
1 answer:
lys-0071 [83]3 years ago
7 0

Answer:

Answer is D

Step-by-step explanation:

hope that helps

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n the above figure, the radius of curvature is 10 ft and the height of the segment is 2 ft. What's the length of the chord? A. 7
Rus_ich [418]
Half the length of the chord is ...
   √(10² -(10 -2)²) = 6

The length of the chord is ...
   D. 12 ft

6 0
3 years ago
15 divided by 2/9 <br> math question
Alja [10]

Answer:

the answer to this is 67.5

6 0
2 years ago
An art gallery is increasing the asking price of its paintings by 60%. A painting now costs $400.00. How much was the painting b
inn [45]

Answer:

$240

Step-by-step explanation:

60% = 0.6

400 divided by 0.6 = 240

6 0
2 years ago
Dan's school is selling tickets to a play. On
katrin [286]

Answer: $9.50

Step-by-step explanation:Let's define the variables:

A = price of one adult ticket.

S = price of one student ticket.

We know that:

"On the first day of ticket sales the school sold 1 adult ticket and 6 student tickets for a total of $69."

1*A + 6*S = $69

"The school took in $150 on the second day by selling 7 adult tickets and student tickets"

7*A + 7*S = $150

Then we have a system of equations:

A + 6*S = $69

7*A + 7*S = $150.

To solve this, we should start by isolating one variable in one of the equations, let's isolate A in the first equation:

A = $69 - 6*S

Now let's replace this in the other equation:

7*($69 - 6*S) + 7*S = $150

Now we can solve this for S.

$483 - 42*S + 7*S = $150

$483 - 35*S = $150

$483 - $150 = 35*S

$333 = 35*S

$333/35 = S

$9.51 = S

That we could round to $9.50

That is the price of one student ticket.

4 0
2 years ago
ILL BRAINLIEST YOU PLEASE HELP ME
Rudik [331]

Answer:

AS IT IS RIGHT ANGLE .

THEREFORE, 1 ANGLE =90°

A=55°,

LET LAST ANGLE BE Y.

THEREFORE, Y=90-55=35°

RATIO OF A:Y=55:35=11/7

RATIO OF ANÔTHER SIDE :X=11:7

HYPOTENOUES=8

THEREFORE8^2=11X^2+7X^2

64=121X^2+49X

6 0
3 years ago
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