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aksik [14]
2 years ago
11

There are 20\%20%20, percent more goblins than wizards in magic club. There are 120120120 goblins in magic club.

Mathematics
1 answer:
Vanyuwa [196]2 years ago
6 0
<h2>600</h2>

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My work's below! ⇣

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First, I'll be using a formula for percentages. ( # x 100 / % )

120 x 100 / 20 = 600

There are 600 wizards in the magic club and 120 goblins.

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<em />

<em>Good luck! </em>

<em>~ pinetreee</em>

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Slove <br>A. 115°<br>B. 58°<br>C. 50°<br>D. 226°​
Diano4ka-milaya [45]

Answer:

C

Step-by-step explanation:

The angle is total is 138 degrees. Part of the entire angle is already given (the 88 degree measure), so all you have to do is subtract 88 from 138, which is 50.

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Marianna [84]

Answer:

no real answer

Step-by-step explanation:

distribute the -4 and combine all of the like terms on the left side = r-8-4r, then -8-3r

then we have 7-3r=-8-3r

from here, we can already tell that there's no real answer. this is because the two -3r will cancel, leaving no variable.

since 7 doesn't equal -8, there is no answer.

if, for example, the value on both sides of the equal sign were the same after the variable was eliminated, then your answer would be all real numbers

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3 years ago
Limit as x approaches infinity: 2x/(3x²+5)
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now, by traditional method, as "x" progresses towards the positive infinitity, it becomes 100, 10000, 10000000, 1000000000 and so on, and notice, the limit of the numerator becomes large.

BUT, notice the denominator, for the same values of "x", the denominator becomes larg"er" than the numerator on every iteration, ever becoming larger and larger, and yielding a fraction whose denominator is larger than the numerator.

as the denominator increases faster, since as the lingo goes, "reaches the limit faster than the numerator", the fraction becomes ever smaller an smaller ever going towards 0.

now, we could just use L'Hopital rule to check on that.

\bf \lim\limits_{x\to \infty}~\cfrac{2x}{3x^2+5}\stackrel{LH}{\implies }\lim\limits_{x\to \infty}~\cfrac{2}{6x}

notice those derivatives atop and bottom, the top is static, whilst the bottom is racing away to infinity, ever going towards 0.
5 0
3 years ago
janet completed 8 math problems in 10 minutes. How long per question did janet spend(in minutes and seconds)?
Dominik [7]
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5 0
3 years ago
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The sales decay for a product is given by S = 70000e^ -0.8x where S is the monthly sales and x is the number of months that have
Gre4nikov [31]

Answer:

After 5.31 months sales will drop below 1000 and 5 months after the end of the campaign sales will be 1282.09

Step-by-step explanation:

Let's find the solutions for the two questions.

First question: How many months after the end of the campaign will sales drop below 1000.

Because the problem asks for how many months, and since 'x' represents month variable, then the problem is asking for 'x'.

Using the same equation for sales we can observe the following:

S=70000*e^{-0.8X}, but we have S which is 1000, so:

1000=70000*e^{-0.8X} which is equal to:

1000/70000=e^{-0.8X} which is equal to:

1/70=e^{-0.8X} by applying ln(x) properties:

ln(1/70)=ln(e^{-0.8X}) which is equal to:

ln(1/70)=-0.8X which is equal to:

ln(1/70)/(-0.8)=X so:

X=5.31 months

Second question: what will be the sales 5 months after the end of the campaign.

Because the problem asks for what will be the sales, and since 'S' represents the sales, then the problem is asking for 'S'.

Using the same equation for sales we can observe the following:

S=70000*e^{-0.8X}, but we have x which is 5 months, so:

S=70000*e^{-0.8*5} which is equal to

S=1282.09

In conclusion, after 5.31 months sales will drop below 1000 and 5 months after the end of the campaign sales will be 1282.09.

8 0
4 years ago
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