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2 years ago

Consider the partial set of values for the functions f(x) and g(x):

Mathematics

1 answer:

Elodia [21]2 years ago

5 0

Step-by-step explanation:

We know that FoG is basically used to first solve g(x) and then we solve f(x). We we just plug in the given values and solve

$f\ o\ g(x)=f(g(x))$

$f\ o\ g(x)=f(g(1))$

$f\ o\ g(x)=f(-1)$

$f\ o\ g(x)=1$

Answer: Option B, 1

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X - 2y = -3 2x + y = -1

bezimeni [28]

Answer:

y = 1

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Step-by-step explanation:

x - 2y = -3, then x = 2y - 3

2x + y = -1

substitute for x:

2(2y - 3) + y = -1

4y - 6 + y = -1

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x = 2 - 3 = -1

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What is the quotient in simplified form ? Need help please

Gre4nikov [31]

Answer:

$-\dfrac{4a^{12}b^8}{5}$

Step-by-step explanation:

The applicable rules of exponents are ...

$\dfrac{1}{a^{-b}}=a^b\\\\a^ba^c=a^{b+c}$

Your ratio simplifies to ...

$\dfrac{-8a^8b^{-2}}{10a^{-4}b^{-10}}=-\dfrac{4}{5}a^{8-(-4)}b^{-2-(-10)}\\\\=-\dfrac{4a^{12}b^8}{5}$

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Please note that simplifying the constants, -8/10 to -4/5, eliminates half the answer choices. Since exponents are only multiplied when a power is raised to a power, you can pretty much eliminate the second choice as being unreasonable. ((a^b)^c = a^(bc))

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