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3 years ago

What is the distance between points F(2, 11) and G(5, 16)? Round off to the nearest whole number

Mathematics

1 answer:

liq [111]3 years ago

6 0

Answer:

Step-by-step explanation:

$d_{FG}=\sqrt{(x_G-x_F)^2+(y_G-y_F)^2}\\\\d_{FG}=\sqrt{(5-2)^2+(16-11)^2}=\sqrt{3^2+4^2}=\sqrt{25}=5$

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What is the sum of 15 and the opposite of 13?

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Answer:

Step-by-step explanation:

15+-13 = 2

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The histogram shows the number of payphones that were active by year in a large city. How many payphones would you expect to be

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Step-by-step explanation:

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3 years ago

5. The superintendent of the local school district claims that the children in her district are brighter, on average, than the g

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Answer:

We conclude that children in district are brighter, on average, than the general population.

Step-by-step explanation:

We are given the following data set:

105, 109, 115, 112, 124, 115, 103, 110, 125, 99

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{1117}{10} = 111.7$

Sum of squares of differences = 642.1

$S.D = \sqrt{\frac{642.1}{49}} = 8.44$

We are given the following in the question:

Population mean, μ = 106

Sample mean, $\bar{x}$ = 111.7

Sample size, n = 10

Alpha, α = 0.05

Sample standard deviation, s = 8.44

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 106\\H_A: \mu > 106$

We use one-tailed(right) t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{111.7 - 106}{\frac{8.44}{\sqrt{10}} } = 2.135$

Now,

$t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = 1.833$

Since,

$t_{stat} > t_{critical}$

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

We conclude that children in district are brighter, on average, than the general population.

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