Answer:
72°
Step-by-step explanation:
Given that the radius(r) of the circle is 10 units and the length of arc ABC is 16π
The length of arc ABC = 
Where θ is the central angle in degrees.
Since the length of arc ABC is 16π,

The angle in a circle = 360°, therefore:
Central angle for arc AB (θ) = 360 - Central angle for arc ABC = 360 - 288 = 72°
Therefore the arc measure of arc AB is 72°
Answer:
x = 14
Step-by-step explanation:
You want to solve for x, right?
(x-5)^(1/2)+5=2
You have it right so far.
(x - 5)^(1/2) = -3
(x - 5) = (-3)^2
x - 5 = 9
x = 9 + 5 = 14
Answer:
2 bears in 2020.
Step-by-step explanation:
We have been given that a new bear population that begins with 150 bears in 2000 decreases at a rate of 20% per year.
We will use exponential decay formula to solve our given problem as:
, where,
y = Final quantity,
a = Initial value,
r = Decay rate in decimal form,
x = Time
Upon substituting our given values in above formula, we will get:

, where x corresponds to year 2000.
To find the population in 2020, we will substitute
in our equation as:



Therefore, 2 bears are there predicted to be in 2020.
Since population is decreasing so population is best described as exponential decay.
Answer:

Now we can find the second central moment with this formula:

And replacing we got:

And the variance is given by:
![Var(X) = E(X^2) - [E(X)]^2](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20-%20%5BE%28X%29%5D%5E2)
And replacing we got:

And finally the deviation would be:

Step-by-step explanation:
We can define the random variable of interest X as the return from a stock and we know the following conditions:
represent the result if the economy improves
represent the result if we have a recession
We want to find the standard deviation for the returns on the stock. We need to begin finding the mean with this formula:

And replacing the data given we got:

Now we can find the second central moment with this formula:

And replacing we got:

And the variance is given by:
![Var(X) = E(X^2) - [E(X)]^2](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20-%20%5BE%28X%29%5D%5E2)
And replacing we got:

And finally the deviation would be:

(a) converges; consider the function <em>f(x)</em> = <em>a</em> ˣ, which converges to 0 as <em>x</em> gets large for |<em>a</em> | < 1. Then the limit is 2.
(b) converges; we have
4ⁿ / (1 + 9ⁿ) = (4ⁿ/9ⁿ) / (1/9ⁿ + 9ⁿ/9ⁿ) = (4/9)ⁿ × 1/(1/9ⁿ + 1)
As <em>n</em> gets large, the exponential terms vanish; both (4/9)ⁿ → 0 and 1/9ⁿ → 0, so the limit is 1.
(c) converges; we know ln(<em>n</em> ) → ∞ and arctan(<em>n</em> ) → <em>π</em>/2 as <em>n</em> → ∞. So the limit is <em>π</em>/2.