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Zanzabum
2 years ago
15

Translate then Solve for the variable:

Mathematics
1 answer:
Sergeu [11.5K]2 years ago
8 0

The linear equation will be 2x + 10 = 5(x - 6). Then the value of the variable x will be 23.33.

<h3>What is the linear system?</h3>

A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.

Translate then Solve for the variable:

The sum of two times a number and 10 is five times the difference between a number and six.

Let the number be x.

Then the equation will be

2x + 10 = 5(x - 6)

Then the value of x will be

2x + 10 = 5x - 60

5x - 2x = 60 + 10

      3x = 70

        x = 23.33

More about the linear system link is given below.

brainly.com/question/20379472

#SPJ1

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What is the arc measure of \stackrel{\LARGE{\frown}}{AC}
algol [13]

Answer:

72°

Step-by-step explanation:

Given that the radius(r) of the circle is 10 units and the length of arc ABC is 16π

The length of arc ABC = \frac{\theta}{360}*2\pi r

Where θ is the central angle in degrees.

Since the length of arc ABC is 16π,

16\pi=\frac{\theta}{360}*2\pi r\\16\pi=\frac{\theta}{360}*2\pi *10\\\theta=\frac{16\pi *360}{2 \pi *10} \\\theta=288^0

The angle in a circle = 360°, therefore:

Central angle for arc AB (θ) = 360 - Central angle for arc ABC = 360 - 288 = 72°

Therefore the arc measure of arc AB is 72°

5 0
3 years ago
(x-5)1/2+5=2<br> (x-5)1/2=-3<br> [(x-5)^1/2]^2=(-3)^2
Studentka2010 [4]

Answer:

x = 14

Step-by-step explanation:

You want to solve for x, right?

(x-5)^(1/2)+5=2

You have it right so far.

(x - 5)^(1/2) = -3

(x - 5)  =  (-3)^2

x - 5 = 9

x = 9 + 5 = 14

3 0
3 years ago
: A new bear population that begins with 150 bears in 2000 decreases at a rate of 20% per year.
d1i1m1o1n [39]

Answer:

2 bears in 2020.

Step-by-step explanation:

We have been given that a new bear population that begins with 150 bears in 2000 decreases at a rate of 20% per year.

We will use exponential decay formula to solve our given problem as:

y=a\cdot (1-r)^x, where,

y = Final quantity,

a = Initial value,

r = Decay rate in decimal form,

x = Time

20\%=\frac{20}{100}=0.20    

Upon substituting our given values in above formula, we will get:

y=150(1-0.20)^x

y=150(0.80)^x, where x corresponds to year 2000.

To find the population in 2020, we will substitute x=20 in our equation as:

y=150(0.80)^{20}

y=150(0.011529215046)

y=1.7293822569    

y\approx 2

Therefore, 2 bears are there predicted to be in 2020.

Since population is decreasing so population is best described as exponential decay.

8 0
3 years ago
g If the economy improves, a certain stock stock will have a return of 23.4 percent. If the economy declines, the stock will hav
dusya [7]

Answer:

E(X) = 23.4* 0.67 -11.9*0.33= 11.759 \%

Now we can find the second central moment with this formula:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) = (23.4)^2* 0.67 +(-11.9)^2*0.33= 413.5965

And the variance is given by:

Var(X) = E(X^2) - [E(X)]^2

And replacing we got:

Var(X) = 413.5965 -(11.759)^2 =275.5105

And finally the deviation would be:

Sd(X) = \sqrt{275.5105}= 16.599 \%

Step-by-step explanation:

We can define the random variable of interest X as the return from a stock and we know the following conditions:

X_1 = 23.4 , P(X_1) =0.67 represent the result if the economy improves

X_2 = -11.9 , P(X_1) =0.33 represent the result if we have a recession

We want to find the standard deviation for the returns on the stock. We need to begin finding the mean with this formula:

E(X) = \sum_{i=1}^n X_i P(X_i)

And replacing the data given we got:

E(X) = 23.4* 0.67 -11.9*0.33= 11.759 \%

Now we can find the second central moment with this formula:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) = (23.4)^2* 0.67 +(-11.9)^2*0.33= 413.5965

And the variance is given by:

Var(X) = E(X^2) - [E(X)]^2

And replacing we got:

Var(X) = 413.5965 -(11.759)^2 =275.5105

And finally the deviation would be:

Sd(X) = \sqrt{275.5105}= 16.599 \%

7 0
3 years ago
Determine whether the sequence converges or diverges. If it converges, find the limit. [Hint:
Zepler [3.9K]

(a) converges; consider the function <em>f(x)</em> = <em>a</em> ˣ, which converges to 0 as <em>x</em> gets large for |<em>a</em> | < 1. Then the limit is 2.

(b) converges; we have

4ⁿ / (1 + 9ⁿ) = (4ⁿ/9ⁿ) / (1/9ⁿ + 9ⁿ/9ⁿ) = (4/9)ⁿ × 1/(1/9ⁿ + 1)

As <em>n</em> gets large, the exponential terms vanish; both (4/9)ⁿ → 0 and 1/9ⁿ → 0, so the limit is 1.

(c) converges; we know ln(<em>n</em> ) → ∞ and arctan(<em>n</em> ) → <em>π</em>/2 as <em>n</em> → ∞. So the limit is <em>π</em>/2.

6 0
3 years ago
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