Answer:
A system of linear equations will have exactly one point of intersection, for example:
2x+y=5
-x+y=2
However, a system of linear equations with no solution will have no points of intersection, for example:
-4x+10y=6
2x-5y=3
Sorry about c. though I'm confused on how a pair of equations can have infinite points of intersection unless x or y equals all real numbers which could happen if x or y both equaled all real numbers maybe
And the point of interesection for the system of equations in the problem you attached as an image is (2,-1)
I attached a photo below, and one of how to graph it
Answer:
Sorry this is late and I think this is right.
They are both parallel, they have the same slope, and do <em>not </em>intersect. If you were to draw a slope out for it, you would find this to be true.
For example: Say the question called for you to explain why there aren't any solutions to these system of inequalities:
<em>y < - 1/2x -3</em>
<em>y > 1/2x + 2</em>
<em>y= -x/2 -3</em> and <em>y= -x/2 + 2 </em>have the same exact slope, are parallel, and never intersect. The first line is 5 units below the second line when x = 0. Because the lines are parallel, it is always below the second line. The solutions of y < - x/2 -3 are the points in the plane below the first line. The solutions of y > 1/2 + 2 are points above the second line.
I hope this helps you. Good luck on whatever you're working on and stay safe! Please let me know if this helped you or didn't.
Slope = 1/2 :)
rise over run (rise/run)
so... 2/4 = 1/2
hope this helps!
Answer:
-14
Step-by-step explanation:
Plug 3 in for x
-2 (3)² + 3 + 1
-2 (9) + 3 + 1
-18 + 3 + 1
-14
