Y = e^tanx - 2
To find at which point it crosses x axis we state that y= 0
e^tanx - 2 = 0
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061
to find slope at that point first we need to find first derivative of funtion y.
y' = (e^tanx)*1/cos^2(x)
now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
It would be answer 4 because 14.85 divided by .05 is 297
The answer is 1.
3^3 = 27
27^-1 = 1/27
1/27 x 27 = 1
I took this test and got this question right.
Answer:
It should be C aka 270°
Step-by-step explanation:
Answer: multiply the other side by 3 also
Step-by-step explanation:
What happens to one side must also happen to the other side. This is the only way to keep equations equal when changing constants and variables
