Ask question

Ask question

All categories

3 years ago

11

Dilip is going to paint a shoebox to use for storage of his trading cards. The shoebox is 23 inches long, 10 inches wide, and 8

inches high find the surface area of the shoebox

1 answer:

chubhunter [2.5K]3 years ago

5 0

The answer is 988 square inches. L=23 W=10 H=8

The equation for surface area is 2(L x W) + 2(L x H) + 2(W x H)

Next, you need to substitute the values into the equation to get:

Surface area= 2(23 x 10) + 2(23 x 8) + 2(10 x 8)

Now finish solving the equation to get an answer of 988 square inches!

You might be interested in

What expression is equivalent to (9x^2 + 2x -7)(x - 4)

Dima020 [189]

Answer: C

Step-by-step explanation:

We can use the expanding rule to get that one if the expressions is

(9x^2 + 2x - 7)x + (9x^2 + 2x - 7)(-4)

3 0

2 years ago

Use Lagrange multipliers to find the maximum and minimum values of (i) f(x,y)-81x^2+y^2 subject to the constraint 4x^2+y^2=9. (i

sp2606 [1]

i. The Lagrangian is

$L(x,y,\lambda)=81x^2+y^2+\lambda(4x^2+y^2-9)$

with critical points whenever

$L_x=162x+8\lambda x=0\implies2x(81+4\lambda)=0\implies x=0\text{ or }\lambda=-\dfrac{81}4$

$L_y=2y+2\lambda y=0\implies2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1$

$L_\lambda=4x^2+y^2-9=0$

If $x=0$ , then $L_\lambda=0\implies y=\pm3$ .
If $y=0$ , then $L_\lambda=0\implies x=\pm\dfrac32$ .
Either value of $\lambda$ found above requires that either $x=0$ or $y=0$ , so we get the same critical points as in the previous two cases.

We have $f(0,-3)=9$ , $f(0,3)=9$ , $f\left(-\dfrac32,0\right)=\dfrac{729}4=182.25$ , and $f\left(\dfrac32,0\right)=\dfrac{729}4$ , so $f$ has a minimum value of 9 and a maximum value of 182.25.

ii. The Lagrangian is

$L(x,y,z,\lambda)=y^2-10z+\lambda(x^2+y^2+z^2-36)$

with critical points whenever

$L_x=2\lambda x=0\implies x=0$ (because we assume $\lambda\neq0$ )

$L_y=2y+2\lambda y=0\implies 2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1$

$L_z=-10+2\lambda z=0\implies z=\dfrac5\lambda$

$L_\lambda=x^2+y^2+z^2-36=0$

If $x=y=0$ , then $L_\lambda=0\implies z=\pm6$ .
If $\lambda=-1$ , then $z=-5$ , and with $x=0$ we have $L_\lambda=0\implies y=\pm\sqrt{11}$ .

We have $f(0,0,-6)=60$ , $f(0,0,6)=-60$ , $f(0,-\sqrt{11},-5)=61$ , and $f(0,\sqrt{11},-5)=61$ . So $f$ has a maximum value of 61 and a minimum value of -60.

5 0

3 years ago

HELP HELP HELP HELP HELP

Anuta_ua [19.1K]

Answer:

Length of base (a) = 5 units

Total Surface Area of Pyramid (T.S.A.) = ?

Now,

T.S.A. = Area of four triangles + Area of base

= $4(\frac{\sqrt{3} }{4})(5^{2}) + 5^{2} = 25\sqrt{3} + 25$ ≈ $68.301sq. units$

7 0

3 years ago

Which of the following is a good cardio-respiratory workout option

inysia [295]

Cardio respiratory workouts contain such activities that help to test and improve ones body's ability to sustain dynamic exercise, using large muscle groups over time.

So, all the options - taking an aerobics class, jumping rope , using the stair-master at the gym all are good options for cardio-respiratory workout.

Hence, option D - all of the above is the answer.

8 0

2 years ago

1 2/3 + 4 1/3 equals?

ahrayia [7]

Answer:

6

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers