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allsm [11]
2 years ago
14

TEK 2A

Mathematics
1 answer:
Naily [24]2 years ago
5 0

The graph which best represents a function with a domain of all real numbers less than or equal to 6 is; Choice A as represented in the attached image.

<h3>Which graph represents the given domain?</h3>

According to the task content;

  • The domain of the graph which means the set of possible values of x is less than or equal to 6.

On this note, it follows that the graph which is characterized by the given domain is as attached.

Read more on graphs;

brainly.com/question/14323743

#SPJ1

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What is the value of x in the equation 32(4x – 1) – 3x = 54 – (x + 2)?
konstantin123 [22]

Answer:

2/3

Step-by-step explanation:

32(4x – 1) – 3x = 54 –(x + 2)

⇒ 32×4x-32-3x= 54-x-2   (using the distributive property)

⇒ 128x-32-3x=54-x-2

Taking terms on x on one side and constant term on other, we get

128x-3x+x= 54-2+32

⇒ 126x= 84

⇒ x= 84/126

⇒ x= 2/3

ik this might not make sense but hope this helps

7 0
3 years ago
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Square root of 9 I'll mark the 1st​
Kitty [74]

Answer:

3

Step-by-step explanation:

4 0
3 years ago
A quadilateral ABCD is drawn to circumcribe a circle . prove that AB+CD=AD+BC
lora16 [44]

Answer:

Helllllp

Step-by-step explanation:

3 0
3 years ago
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Liam finds the perfect scarf as a gift for his mother. He uses his debit card to buy the scarf. What is an advantage of using a
Hoochie [10]
Well a debit card is the card that draws money directly out of your bank account, A credit is the money your going to have to pay back with interest so your best option would be B)
5 0
3 years ago
Given the set of vertices, determine whether parallelogram ABCD is a rhombus, rectangle or square. List all that apply. A(7,-4),
Sloan [31]

Given:

Vertices of a parallelogram ABCD are A(7,-4), B(-1,-4), C(-1,-12), D(7, -12).

To find:

Whether the parallelogram ABCD is a rhombus, rectangle or square.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

AB=\sqrt{(-4-(-4))^2+(-1-7)^2}

AB=\sqrt{(-4+4)^2+(-8)^2}

AB=\sqrt{0+64}

AB=8

Similarly,

BC=\sqrt{(-1-(-1))^2+(12-(-4))^2}=8

CD=\sqrt{(7-(-1))^2+(-12-(-12))^2}=8

AD=\sqrt{(7-7)^2+(-12-(-4))^2}=8

All sides of parallelogram are equal.

AC=\sqrt{(-1-7)^2+(-12-(-4))^2}=8\sqrt{2}

BD=\sqrt{(7-(-1))^2+(-12-(-4))^2}=8\sqrt{2}

Both diagonals are equal.

Since, all sides are equal and both diagonals are equal, therefore, the parallelogram ABCD is a square.

We know that, a square is special case of rectangles and rhombus.

So, parallelogram ABCD is a rhombus, rectangle or square. Therefore, the correct option is c.

7 0
3 years ago
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