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2 years ago

TEK 2A

1 answer:

5 0

The graph which best represents a function with a domain of all real numbers less than or equal to 6 is; Choice A as represented in the attached image.

<h3>Which graph represents the given domain?</h3>

According to the task content;

The domain of the graph which means the set of possible values of x is less than or equal to 6.

On this note, it follows that the graph which is characterized by the given domain is as attached.

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The observation deck is about 20 m above sea level. From the observation deck, the angle of depression of the boat is 6 degrees.

Leno4ka [110]

θ\ 6 degrees
    \
\ so the θ= 180-90-6 =84 degrees so we need to find x
20m   \ tan (84)=x/20
  ____  \ x=20 tan(84)
x x=190.287

7 0

3 years ago

Simplyfi. (9g^10p^8)^2<br> givin brainlest to first correct

Cloud [144]

Answer:

$= 9 {g}^{20} {p}^{16}$

hope this helps

brainliest appreciated

good luck! have a nice day!

3 0

3 years ago

The Diagram shows the net of a square pyramid and its dimensions

Serjik [45]

<u>Answer:</u>

<u>Explanation:</u>

SA = the area of one side of the pyramid times 4 + the area of the base of the pyramid

Area of a triangle = (height × base)/2

Area of a sqaure = lenght²

given:

h = 4 ft | b = 6 ft | l = 6 ft

SA = 4(h×b×1/2) + l²

SA = 4(4×6×1/2) + 6²

SA = 4×12 + 36

SA = 48 + 36

SA = 84 ft²

3 0

3 years ago

If function f is a cubic polynomial which statement most accurately describes the function over the interview (0,1)

inysia [295]

Answer:

Option (B)

Step-by-step explanation:

From the given table,

With the increase in the values of x (from x = -2 to x = 2), values of the function is decreasing from x =2 to x = 4.

Interval (0, 1) lies in the domain of the function in which the y-values of the function are,

At x = 0,

f(0) = -6

At x = 1,

f(1) = 0

Therefore, values of the given function are increasing in the interval of (0, 1).

Option (B) will be the correct option.

7 0

3 years ago

Consider f and c below. f(x, y, z) = (y2z + 2xz2)i + 2xyzj + (xy2 + 2x2z)k,

qaws [65]

$\dfrac{\partial f}{\partial x}=y^2z+2xz^2$
$f(x,y,z)=xy^2z+x^2z^2+g(y,z)$

$\dfrac{\partial f}{\partial y}=2xyz+\dfrac{\partial g}{\partial y}=2xyz$
$\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)$

$\dfrac{\partial f}{\partial z}=xy^2+2x^2z+\dfrac{\mathrm dh}{\mathrm dz}=xy^2+2x^2z$
$\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=0$

$\implies f(x,y,z)=xy^2z+x^2z^2+C$

8 0

3 years ago