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3 years ago

Find the sum: 2.97 + 0.43 A) 2.54 B) 3.40 C) 3.47 D) 4.00

Mathematics

2 answers:

Ivahew [28]3 years ago

6 0

Answer:

B. 3.40

Step-by-step explanation:

To make it simpler, first add 0.03 to 2.97 to get 3.

then add 0.40 to 3 and you get 3.40.

Ket [755]3 years ago

3 0

Answer:3.40

Ur welcome

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A train pulls into a station and lets off its passengers. please help!

Vladimir [108]

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Step-by-step explanation:

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2 years ago

10 < 0.25 ( x + 1 ) < 11

AURORKA [14]

10 <0.25 (x + 1) <11
We must solve two inequalities in this case.
Inequality 1:
10 <0.25 (x + 1)
10 / 0.25 <x + 1
40 <x + 1
40-1 <x
39 <x
Inequality 2:
0.25 (x + 1) <11
(x + 1) <11 / 0.25
(x + 1) <44
x <44-1
x <43
The final result is:
39 <x <43
Answer:
39 <x <43

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3 years ago

1+secA/sec A = sin^2 A / 1-cos A

Fofino [41]

Answer: see proof below

<u>Step-by-step explanation:</u>

$\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}$

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

<u>Proof LHS → RHS</u>

$\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}$

$\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}$

$\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}$

$\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}$

$\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}$

$\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark$

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3 years ago

A triangle has one side that measures 12 inches and another side that measures 33 inches. Which are possible side lengths of the

In-s [12.5K]

Answer:

Greater than 21

Less than 45

Step-by-step explanation:

You add and subtract the two numbers you are given.

33 - 12 = 21

The third side has to be bigger than 21.

33 + 12 = 45

The third side has to be less than 45.

It can be written in one math sentence:

21 < x < 45

5 0

2 years ago