Given the balanced equation:
( Reaction type : double replacement)
CaF2 + H2SO4 → CaSO4 + 2HFI
We can determine the number of grams prepared from the quantity of 75.0 H2SO4, and 63.0g of CaF2 by converting these grams to moles per substance.
This can be done by evaluating the atomic mass of each element of the substance, and totaling it to find the molecular mass.
For H2SO4 or hydrogen sulfate it's molecular mass is the sum of the quantity of atomic mass per element. H×2 + S×1 + O×4 = ≈1.01×2 + ≈32.06×1 + ≈16×4 = 2.02 + 32.06 + 64 = 98.08 u (Dalton's or Da) or g / mol.
For CaF2 or calcium fluoride, it's molecular mass adds 1 atomic mass of calcium and 2 atomic masses of fluoride due to the number of atoms.
Ca×1 + F×2 = ≈40.07×1 + ≈19×2 = 40.08 + 38 = 78.07 u (Da or Dalton's) or g / mol.
Answer: 11.5 grams
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution
where,
Morality = 0.612 M
n= moles of solute
= volume of solution in ml = 100 ml
Now put all the given values in the formula of molarity, we get
Therefore, the mass of copper (II)nitrate required is 11.5 grams
(C) neon (atomic number 10)
Explanation:
The atom that is chemically inert is Neon with an atomic number of 10.
An atom is chemically inert if it does not willingly take part in chemical reaction.
Atoms takes part in chemical reactions in order to attain a stable configuration as seen in the noble gases.
In the noble gases every enable level is completely filled with the appropriate number of electrons.
- The noble gases are He, Ne, Ar, Kr, Xe
- These elements do not react with others.
- From the given option, Neon is a noble gas and therefore inert.
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Answer: i could be incorrect but im pretty sure the answer is, Gas surface with no rings.
Explanation:
s-s-s-science!
Answer:
Explanation:
Hello,
In this case, for the given reactants we identify the following chemical reaction:
Thus, we evidence a 1:1 molar ratio between KOH and HCl, therefore, for the complete neutralization we have equal number of moles, that in terms of molarities and volumes become:
Hence, we compute the volume of HCl as shown below:
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