The electrons are transferred from potassium to sulphur, in this reaction, potassium is being oxidised and sulphur is being reduced. Two potassium atoms each lose one electron forming K+ ions. Sulphur gains two electrons forming S2-/2- ions. The resultant formula will be: K2S, bonding in this compound is ionic.
The osmotic pressure of a solution is a colligative property, which means that it depends on the number of particles of solute in the solution.
Formula: Osmotic pressure = MRT, where M is the molarity of the solution, R is the universal constant of ideal gases and T is the absolute temperature of the solution.
So, the answer is the option .: the osmotic pressure of a solution increases as the number of particles of solute in the solution increases.
Answer:
Ionic bond is formed by the opposite ions attraction between the 2 atoms in an ionically bonded compound. The two ions i.e. Cation and Anions are formed by oxidation and reduction reactions respectively. General Ionic formula is as follow,
Mⁿ⁺ + Nⁿ⁻ → MN
where;
Mⁿ⁺ = Cation
Nⁿ⁻ = Anion
MN = Salt
Explanation:
Ionic bond is the electrostatic forces of attraction between positively charged cations and negatively charged Anions. These forces are very stronger resulting in increasing several physical properties of Ionic compounds like melting point and boiling point e.t.c.
Example:
Sodium Chloride:
NaCl is formed by Na⁺ cation and Cl⁻ anion as follow,
Oxidation of Na;
2 Na → 2 Na⁺ + 2 e⁻
Reduction of Cl₂;
Cl₂ + 2 e⁻ → 2 Cl⁻
Crystal Lattice formation is as follow,
Na⁺ + Cl⁻ → NaCl
Based on the charge on the aluminium ion, 0.9 g of aluminium are deposited by 0.1 F of electricity.
<h3>What is electrolysis?</h3>
Electrolysis is the decomposition of a substance known as an electrolyte when electric current is passed through it.
The mass and hence moles an electrolyte deposited when current is passed through it depends on the charge on the ion.
Aluminium ion has a charge of +3 and requires 3F of electricity to deposit 1 mole or 27 g of aluminium
0.1 F will discharge = 0.1/3 × 27 g of aluminium
mass of aluminium deposited = 0.9 g of aluminium.
Therefore, 0.9 g of aluminium are deposited by 0.1 F of electricity.
Learn more about electrolysis at: brainly.com/question/26050361
