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gizmo_the_mogwai [7]
3 years ago
8

PLZZZZZZZ HELP MEEEEEE!!!!!!!!!!

Chemistry
1 answer:
nikitadnepr [17]3 years ago
7 0

Answer:

Its Obviously Dinosaurs

Explanation: They died 65 million years ago

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A. The force of gravity.

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What’s the answer for number 2?
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The answer to this is surface wave i think
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Acetonitrile major species present when dissolved in water
IrinaVladis [17]

Acetonitrile refers to the chemical compound exhibiting the formula CH₃CN. It is the basic organic nitrile and a colorless liquid. It is generated primarily as a byproduct of acrylonitrile production. It is used as a polar aprotic solvent in the purification of butadiene and in organic synthesis.  

The addition of water to cyanides generates amines and acids. Acetonitrile produces ammonia and acetic acid.  

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3 0
3 years ago
Determine the mass of SO₂ that contains 6.075 × 10^26 S atoms.​
Misha Larkins [42]

Avogadro's law states that in a mole of any substance, there are 6.022 \times 10^{23} atoms. This means that in the given sample, there are

\frac{6.075 \times 10^{26}}{6.022 \times 10^{23}}=1008.8010627 \text{ mol}

  • The atomic mass of sulfur is 32.06 amu.
  • The atomic mass of oxygen is 15.9994 amu.

So, the atomic mass of sulfur dioxide is

32.06+2(15.9994=64.0588 \text{ g/mol}

Therefore, the mass is:

(64.0588)(1008.8010627)=\boxed{64620 \text{ g (to 4 sf)}}

7 0
2 years ago
During lab, a student used a Mohr pipet to add the following solutions into a 25 mL volumetric flask. They calculated the final
kompoz [17]

Answer:

(FeSCN⁺²) = 0.11 mM

Explanation:

Fe ( NO3)3 (aq) [0.200M] + KSCN (aq) [ 0.002M] ⇒ FeSCN+2

M (Fe(NO₃)₃  = 0.200 M

V (Fe(NO₃)₃ =  10.63 mL

n (Fe(NO₃)₃ = 0.200*10.63 = 2.126 mmol

M (KSCN) =  0.00200 M

V (KSCN) = 1.42 mL

n (KSCN) =  0.00200 * 1.42 = 0.00284 mmol

Total volume = V (Fe(NO₃)₃  + V (KSCN)

                       = 10.63 + 1.42

                       = 12.05 mL

Limiting reactant = KSCN

So,

FeSCN⁺² = 0.00284 mmol

M (FeSCN⁺²) = 0.00284/12.05

                     = 0.000236 M

Excess reactant = (Fe(NO₃)₃

n(Fe(NO₃)₃ =  2.126 mmol -  0.00284 mmol

                  =2.123 mmol

For standard 2:

n (FeSCN⁺²) = 0.000236 * 4.63

                    =0.00109

V(standard 2) = 4.63 + 5.17

                       = 9.8 mL

M (FeSCN⁺²)  = 0.00109/9.8

                      = 0.000111 M = 0.11 mM

Therefore, (FeSCN⁺²) = 0.11 mM

7 0
3 years ago
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