Answer:
Step-by-step explanation:
<h3>#10</h3>According to diagram we have
Conclusion
ABC and DCB are right triangles but corresponding sides have different ratio
So triangles are not similar
<h3>#12</h3>According to Pythagorean the missing hypotenuse is
The triangles have three congruent pairs of sides (3, 4 and 5 units) so are congruent by SSS (or HL)
Yeah Imao you usually do these type of questions on a calculator but I've tried writing it on a calculator and it keeps on saying "error" so I'm gonna guess the question is wrong or sth
but if you type out the question without the bracket before the 12 you'll get 6.63
anyway hope this helps- have a good day bro cya)
<u>Answer:</u>
The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.
<u>Solution:</u>
Given, Scores on a test are normally distributed with a mean of 81.2
And a standard deviation of 3.6.
We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?
For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6
Now probability of getting more than 88.4 = 1 - area of z – score of 88.4
So, probability of getting more than 88.4 = 1 – area of z- score(2)
= 1 – 0.9772 [using z table values]
= 0.0228.
Now probability of getting more than 77.6 = 1 - area of z – score of 77.6
So, probability of getting more than 77.6 = 1 – area of z- score(-1)
= 1 – 0.1587 [Using z table values]
= 0.8413
Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185
Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.