(f+g)(x) = f(x) + g(x)
(f+g)(x) = 3x-2 + 2x+1
(f+g)(x) = (3x+2x) + (-2+1)
(f+g)(x) = 5x - 1
There are 10 balls in the Urn Total.
Red: 6
Green: 4
Question One: The probability that five red and two green is selected is likely. (as that is over half for both)
Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.
Question Three: At least four is likely, as there is more red then green in the Urn.
Hope I helped!
(Mark Brainliest if you can please!)
Answer:
2
Step-by-step explanation:
We are given that a decimal number d
d=0.12345678...
Where d is formed by writing in succession all the positive integers in increasing order after decimal point.
We have to find the 100th digit of d to the right of the decimal point.
Place of first digit 1 after decimal=Tenth
Place of second digit 2 after decimal=Hundredth
Place of third digit 3 after decimal=Thousandth
Therefore, 100th digit of d to the right of the decimal point=2
I think its the first one
