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3 years ago

10

PLEASE HELP! Will mark brainliest! Find the slope of the line:

2 answers:

balandron [24]3 years ago

8 0

Answer:

the final answer is 4/5

Step-by-step explanation:

well the slope formula is the following:

m= (change in y)/(change in x)

let's take the two following points

(-3,0) and (2,4) so

x_1=-3\\x_2=2\\y_1=0\\y_2=4

so

change in y = y_2-y_1=4-0

change in x = x_2-x_1=2-(-3)=2+3=5

so

m=4/5

adelina 88 [10]3 years ago

4 0

Answer:

the slope is 4/5

Step-by-step explanation:

well the slope formula is the following:

m= (change in y)/(change in x)

let's take the two following points

(-3,0) and (2,4) so

$x_1=-3\\x_2=2\\y_1=0\\y_2=4$

so

change in y = $y_2-y_1=4-0$

change in x = $x_2-x_1=2-(-3)=2+3=5$

so

m=4/5

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This is the question i need help with

vekshin1

I'm pretty sure it should be the 45. or A

4 0

3 years ago

Please show work, i’ll mark as brainliest

bulgar [2K]

Answer:

y=4

x=-3

Step-by-step explanation:

4(-3)-9y=-48

-12-9y=-48

-9y=-36

y=4

x=-3

4 0

3 years ago

Read 2 more answers

Lunch break: In a recent survey of 655 working Americans ages 25-34, the average weekly amount spent on lunch was $43.5

Inga [223]

Using the Empirical Rule, it is found that:

a) Approximately 99.7% of the amounts are between $35.26 and $51.88.
b) Approximately 95% of the amounts are between $38.03 and $49.11.
c) Approximately 68% of the amounts fall between $40.73 and $46.27.

------------

The Empirical Rule states that, in a <em>bell-shaped </em>distribution:

Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.

-----------

Item a:

$43.5 - 3(2.77) = 35.26$

$43.5 + 3(2.77) = 51.88$

Within <em>3 standard deviations of the mean</em>, thus, approximately 99.7%.

-----------

Item b:

$43.5 - 2(2.77) = 38.03$

$43.5 + 2(2.77) = 49.11$

Within 2<em> standard deviations of the mean</em>, thus, approximately 95%.

-----------

Item c:

68% is within 1 standard deviation of the mean, so:

$43.5 - 2.77 = 40.73$

$43.5 + 2.77 = 46.27$

Approximately 68% of the amounts fall between $40.73 and $46.27.

A similar problem is given at brainly.com/question/15967965

8 0

3 years ago

Read 2 more answers

There are 33 liters of orange juice at a school party. 1010 students want to drink all of the orange juice, and they all want to

skelet666 [1.2K]

Answer: 0.033 liters or 33 ml each

Step-by-step explanation:

There are 33 liters of orange juice and 1,010 students to drink it.

If they are to drink an equal amount, you should divide the quantity of orange juice by the number of students who want to drink it:

= Quantity of orange juice / Number of students drinking

= 33 / 1,010

= 0.033 liters each

In milliliters this would be:

= 0.033 * 1,000 milliliters

= 33 ml each

6 0

3 years ago

Read 2 more answers

Use the alternative form of the dot product to find u · v.

vodka [1.7K]

Answer:

Step-by-step explanation:

u = 45

v = 30

Angle between them, θ = 5π / 6 = 150°

(a) The formula for the dot product is given by

$\overrightarrow{u}.\overrightarrow{v}= u v Cos\theta$

$\overrightarrow{u}.\overrightarrow{v}= 45 \times 30 \times Cos150$

$\overrightarrow{u}.\overrightarrow{v}= -1169.13$

(b) $\overrightarrow{u}=Cos\frac{\pi }{3}\widehat{i}+Sin\frac{\pi }{3}\widehat{j}$

$\overrightarrow{u}=0.5\widehat{i}+0.866\widehat{j}$

$\overrightarrow{v}=Cos\frac{2\pi }{3}\widehat{i}+Sin\frac{2\pi }{3}\widehat{j}$

$\overrightarrow{v}=-0.707\widehat{i}+0.707\widehat{j}$

Let the angle between them is θ

The formula in terms of the dot product is given by

$Cos\theta =\frac{\overrightarrow{u}.\overrightarrow{v}}{u v}$

$u=\sqrt{0.5^{2}+0.866^{2}}=1$

$v=\sqrt{-0.707^{2}+0.707^{2}}=1$

$Cos\theta =\frac{0.5 \times (-0.707) + 0.866 \times 0.707)}{1\times 1}$

$Cos\theta=0.2587$

θ = 75°

(c) $\overrightarrow{u}=1\widehat{i}+4\widehat{j}+8\widehat{k}$

$u=\sqrt{1^{2}+4^{2}+8^{2}}=9$

$Cos\alpha =\frac{1}{9}$

$Cos\beta =\frac{4}{9}$

$Cos\gamma =\frac{8}{9}$

7 0

3 years ago