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Julli [10]
2 years ago
9

2 1/3 ÷ 1 3/4-2.6÷1.3 pls i rlly need help anything will help

Mathematics
1 answer:
Nat2105 [25]2 years ago
3 0

Answer:

The answer is -2/3

Step-by-step explanation:

Multiply by the reciprocal:

7/3 / 1/4 x 2

Simplify expression:

7/3 x 4/7 -2

Calculate:

1/3 x 4 -2

4/3 - 2

= -2/3

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gladu [14]

Answer:

41

Step-by-step explanation:

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Suzanne bought a sweater at the sale price of $25. The original cost of the sweater was $40. What percent represents that discou
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Solve for xx. Write the smaller solution first, and the larger solution second. X^2 + 12x + 27 = 0x 2 +12x+27=0
sineoko [7]

Answer:

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Step-by-step explanation:

x^2 + 12x + 27 = 0

We need 2 numbers whose product is  + 27 and whose sum is + 12. These are 3 and 9. So the factors are:-

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7 0
3 years ago
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Suppose 10000 people are given a medical test for a disease. About1% of all people have this condition. The test results have a
Alina [70]

Answer:

The percent of the people who tested positive actually have the disease is 38.64%.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person has the disease

<em>P</em> = the test result is positive

<em>N</em> = the test result is negative

Given:

P(X)=0.01\\P(P|X^{c})=0.15\\P(N|X)=0.10

Compute the value of P (P|X) as follows:

P(P|X)=1-P(P|X^{c})=1-0.15=0.85

Compute the probability of a positive test result as follows:

P(P)=P(P|X)P(X)+P(P|X^{c})P(X^{c})\\=(0.85\times0.10)+(0.15\times0.90)\\=0.22

Compute the probability of a person having the disease given that he/she was tested positive as follows:

P(X|P)=\frac{P(P|X)P(X)}{P(P)}=\frac{0.85\times0.10}{0.22} =0.3864

The percentage of people having the disease given that he/she was tested positive is, 0.3864 × 100 = 38.64%.

3 0
3 years ago
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