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Fantom [35]
2 years ago
7

Ajay wraps a gift box in the shape of a triangular pyramid. The figure below shows a

Mathematics
1 answer:
Arisa [49]2 years ago
5 0

Ajay wraps a gift box in the shape of a triangular pyramid. The amount

of wrapping paper he uses is 173.2 square inches.

<h3>How to calculate the surface area of a triangular pyramid?</h3>

The formula for calculating the total surface area is expressed as:

Area = 4(area of triangle)

The area of the triangle

A = 0.5(8.66)(10)

A = 43.3 square inches

The total surface area will be

TSA = 4(43.3)

TSA = 173.2 square inches

Hence the amount of wrapping paper Ajay uses is 173.2 square inches

Learn more on the total surface area here:

brainly.com/question/1297098

#SPJ1

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Which type of deposit is paid in advance to protect landlords against nonpayment?
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Need answers ASSAP
ollegr [7]
Data:
r (radius) = 3.5 in
h (height) = 8 in
Adopt: \pi \approx3.14
V (volume) = ?
Ink cost per cubic inch = $0.05/in³
Total cost: ?

<span>Calculate the volume of the paint bucket (its formed being cylindrical), we have:
</span>V =  \pi *r^2*h 
V = 3.14 *3.5^2*8 
V = 3.14*12.25*8
\boxed{V = 307.72\:in^3}

<span>What was the total cost of the paint?

</span>price($)___measure(in³)
0.05 ---------- 1
y -------------- 307.72

It is made the rule of three: (<span>directly proportional)
</span>
\frac{0.05}{y} = \frac{1}{307.72}
multiply cross
1*y = 0.05*307.72
y = 15.386\:\to\:\boxed{\boxed{y\approx\$15}}\end{array}}\qquad\quad\checkmark

Answer:
<span>the total cost of the paint is $15</span>
7 0
3 years ago
Question 2 of 5
AlekseyPX

Given:

The different recursive formulae.

To find:

The explicit formulae for the given recursive formulae.

Solution:

The recursive formula of an arithmetic sequence is f(n)=f(n-1)+d, f(1)=a,n\geq 2 and the explicit formula is f(n)=a+(n-1)d, where a is the first term and d is the common difference.

The recursive formula of a geometric sequence is f(n)=rf(n-1), f(1)=a,n\geq 2 and the explicit formula is f(n)=ar^{n-1}, where a is the first term and r is the common ratio.

The first recursive formula is:

f(1)=5

f(n)=f(n-1)+5 for n\geq 2.

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 5. So, the explicit formula for this recursive formula is:

f(n)=5+(n-1)(5)

f(n)=5+5(n-1)

Therefore, the correct option is A, i.e., f(n)=5+5(n-1).

The second recursive formula is:

f(1)=5

f(n)=3f(n-1) for n\geq 2.

It is the recursive formula of a geometric sequence with first term 5 and common ratio 3. So, the explicit formula for this recursive formula is:

f(n)=5(3)^{n-1}

Therefore, the correct option is F, i.e., f(n)=5(3)^{n-1}.

The third recursive formula is:

f(1)=5

f(n)=f(n-1)+3 for n\geq 2.

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 3. So, the explicit formula for this recursive formula is:

f(n)=5+(n-1)(3)

f(n)=5+3(n-1)

Therefore, the correct option is D, i.e., f(n)=5+3(n-1).

6 0
3 years ago
Read 2 more answers
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