What is the difference between Glasgow and Copenhagen. (Glasgow= -7.8 Copenhagen=-3.8)

What is the area of ABC?

notsponge [240]

Let D be the Intersection of Height of the Triangle and Base of the Triangle BC

From the Figure, We can notice that Triangle ADB is a Right angled Triangle.

We know that, In a Right angled Triangle :

$\bigstar$ (Hypotenuse)² = (First Leg)² + (Second leg)²

In Triangle, ADB : AB is the Hypotenuse, AD is the First leg and BD is the Second leg

Given : AB = 15 and BD = 9

Substituting the values, We get :

$:\implies$ (15)² = (AD)² + (9)²

$:\implies$ 225 = (AD)² + 81

$:\implies$ (AD)² = 225 - 81

$:\implies$ (AD)² = 144

$:\implies$ (AD)² = (12)²

$:\implies$ AD = 12

We know that, In a Right angled Triangle :

$\bigstar\;\;\boxed{\mathsf{Tan\theta = \dfrac{Opposite\;Side}{Adjacent\;Side}}}$

Now, Consider Triangle ADC : With respect to 45° Angle, AD is the Opposite Side and DC is the Adjacent Side

$:\implies \mathsf{In\;Triangle\;ADC,\;Tan45^{\circ} = \dfrac{AD}{DC}}$

$\mathsf{:\implies 1 = \dfrac{12}{DC}}$

$:\implies$ DC = 12

$:\implies$ Total Length of the Base (BC) = BD + DC

$:\implies$ Total Length of the Base (BC) = 9 + 12

$:\implies$ Total Length of the Base (BC) = 21

We know that, Area of the Triangle is given by :

$\bigstar\;\;\boxed{\mathsf{Area = \dfrac{1}{2} \times Base \times Height}}$

In Triangle, ABC : AD is the Height and BC is the Base

$:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = \dfrac{1}{2} \times BC \times AD}$

$:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = \dfrac{1}{2} \times 21 \times 12}$

$:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = (21 \times 6)}$

$:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = 126}$

7 0

4 years ago

Fiona is trying to prove that a pair of expressions are equivalent by using substitution. Which pair of expressions have the sam

Anna71 [15]

Answer:

B let me know if I got it right or not :)

6 0

4 years ago

Read 2 more answers

FAST!!!NEED HELP!!!!

kipiarov [429]

Answer:that is one by on and the answer is 546$ 638

Step-by-step explanation:

7 0

4 years ago

the length of Marshall's rectangular poster is 2 times its width. If the perimeter is 24 inches, what is the area of the poster

kherson [118]

Recall that perimeter of a rectangle can be expressed by 2l + 2w = p, in which l is the length and w is the width.
If the perimeter of a rectangle is 24 inches, we can plug that into the equation and we get the following:
2l + 2w = 24
Now, using the other bit of info, that the length is twice the width, we can create a second equation:
l = 2w
Now, we can plug in l into our value for 2w in our original equation using substitution.
2l + l = 24
By combining like terms, we get this:
3l = 24
Now if we divide both sides by 3, we get that the length equals 8.

Now we can plug 8 into our original equation in place of l.
2(8) + 2w =24
16 + 2w = 24
Subtract 16 from both side:
2w=8
Divide both sides by 2:
w=4

Now we have both the length and the width! We also know that the values are correct because 8, the length, is two times 4, the width.
Now we need to multiply these together to get the area.
8 x 4 = 32
And there you have it! 32 square units is the area.

3 0

3 years ago

Read 2 more answers

A) the quantity in column A is larger

Crank

Answer: A

The number of distinctive prime factors in Column A is <u>60.</u>

The number of distinctive prime factors in Column B is <u>30.</u>

This number is 1/2 half more prime factors.

There is 30 more prime factors, so the answer is A.

The quantity in column A is larger than column B.

7 0

4 years ago