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2 years ago

Suppose a universal set consists of natural numbers that

Mathematics

1 answer:

LenKa [72]2 years ago

5 0

To set up a venn diagram, you need the following details below

Set A = ( 3, 6, 9, 12, 15 )
Set B = ( 1, 3, 5, 7, 9. 11, 13, 15 )
A∩B = ( 3, 9 )
U = (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16)

<h3>Meaning of a set and a venn diagram</h3>

A set is the orderly collection of elements, material, numbers and items that satisfy a condition.

A set could be finite or infinite.

A venn diagram is a diagramatic representation of a set using circles. it mostly represents a finite set.

In conclusion, you can use the details above to draw your venn diagram.

Learn more about venn diagrams : brainly.com/question/20795347

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Use the figure to answer the questions below.

alina1380 [7]

Answer:

parallelogram
x = 5
60 units

Step-by-step explanation:

A. Opposite sides are the same length, so the figure is a parallelogram.

B. Diagonals of a parallelogram cross at their midpoints, so ...

9x +3 = 10x -2

5 = x . . . . . . . . add 2-9x to both sides

C. The longer side is 12x = 12(5) = 60 . . . . units

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3 years ago

The equation below describes a proportional relationship between x and y. What is the constant of proportionality?

mamaluj [8]

Answer:

Step-by-step explanation:

whats 9 + 10

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3 years ago

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Round 75.4614 to the nearest thousandth

Anna11 [10]

$75.4614\approx75.461$

6 0

3 years ago

Can anyone explain tonme how to do this please?

Mars2501 [29]

C is right. She has partially completed the construction. Her next step is to use the arc markings to determine the radius to construct the circle.

4 0

3 years ago

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100 POINTS AND BRAINLIEST

zysi [14]

Answer:

8 square units and $\frac{40}{3}$ square units

Step-by-step explanation:

The area of the triangle ABC is 24 square units.

1. Triangles ABC and FBG are similar with scale factor $\frac{1}{3},$ then

$\dfrac{A_{\triangle FBG}}{A_{\triangle ABC}}=\dfrac{1}{9}\Rightarrow A_{\triangle FBG}=\dfrac{1}{9}\cdot 24=\dfrac{8}{3}\ un^2.$

2. Triangles ABC and DBE are similar with scale factor $\frac{2}{3},$ then

$\dfrac{A_{\triangle DBE}}{A_{\triangle ABC}}=\dfrac{4}{9}\Rightarrow A_{\triangle DBE}=\dfrac{4}{9}\cdot 24=\dfrac{32}{3}\ un^2.$

3. Thus, the area of the quadrilateral DFGE is

$A_{DFGE}=A_{\triangle DBE}-A_{\triangle FBG}=\dfrac{32}{3}-\dfrac{8}{3}=8\ un^2.$

and the area of the quadrilateral ADEC is

$A_{ADEC}=A_{\triangle ABC}-A_{\triangle DBE}=24-\dfrac{32}{3}=\dfrac{40}{3}\ un^2.$

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3 years ago

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