<span>There are several possible events that lead to the eighth mouse tested being the second mouse poisoned. There must be only a single mouse poisoned before the eighth is tested, but this first poisoning could occur with the first, second, third, fourth, fifth, sixth, or seventh mouse. Thus there are seven events that describe the scenario we are concerned with. With each event, we want two particular mice to become diseased (1/6 chance) and the remaining six mice to remain undiseased (5/6 chance). Thus, for each of the seven events, the probability of this event occurring among all events is (1/6)^2(5/6)^6. Since there are seven of these events which are mutually exclusive, we sum the probabilities: our desired probability is 7(1/6)^2(5/6)^6 = (7*5^6)/(6^8).</span>
Answer:
Yes
Step-by-step explanation:
Yes
Answer:
(-6,1) (-12,2) (-18,3) (-24,4) (-30,5)
Hope this helps!
Answer:
x = 54.6 m
Step-by-step explanation:
Δ MAB and Δ MNP are similar, then corresponding sides are in proportion, that is
= 
, substitute values
= 
= ( cross- multiply )
80.5x = 4395.3 ( divide both sides by 80.5 )
x = 54.6
Since every side of a square is the same length, and the formula to find the area is bh you would just do 2.75²
2.75×2.75=7.5625≈7.56
the answer is the area of the square is approximately 7.56u²
