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2 years ago

Help please thank u!!

Mathematics

1 answer:

gtnhenbr [62]2 years ago

7 0

Answer:

E={1,2,3}

Step-by-step explanation:

First one is the correct answer

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PLS HELP ME!! Jdjjssnbshsnsvgzhshsvssu

Ivahew [28]

Answer: The 2 litter bottle holds more

Step-by-step explanation:

3 0

3 years ago

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The average cost per person of attending an online class depends on the number of people attending. If 20 people attend, the web

kondaur [170]

Answer:

The last table given See attached image)

Step-by-step explanation:

Notice that they are asking for the inverse function to the one with the detailed relationship given. The original relationship was assigning to the Domain of number of people attending, the Range of values for charges.

Therefore, the inverse function will be assigning in the opposite way: from the average charges (now the Domain of this relationship), to the number of people attending (now the Range of this relationship). The relationship should also maintain the original element to element connection:

What was:

(20, $10) should now be ($10, 20)

(26, $6.25) should now be ($6.25, 26)

(35, $4) should now be ($4, 35)

This is exactly represented by the last table (see also image attached)

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3 years ago

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The fox population in a certain region has a continuous growth rate of 5% per year. It is estimated that the population in the y

kvasek [131]

Answer:

P(t) = A * (1 + r)^t ;

14,922 ;

Year 2013

Step-by-step explanation:

Given the following :

Continuous growth rate(r) = 5% = 0.05

Population in year 2000 = Initial population (A) = 10,100

Time(t) = period (years since year 2000)

Find a function that models the population,P(t) , after (t) years since year 2000 (i.e. t= 0 for the year 2000).

P(t) = A * (1 + r)^t

Trying out our function for t = year 2000, t =0

P(0) = 10,100 * (1 + 0.05)^0

P(0) = 10,100 * 1.05^0 = 10,100

B.)

Use your function from part (a) to estimate the fox population in the year 2008.

Year 2008, t = 8

P(8) = 10,100 * (1 + 0.05)^8

P(8) = 10,100 * 1. 05^8

P(8) = 10,100 * 1.4774554437890625

= 14922.29

= 14,922

c) Use your function to estimate the year when the fox population will reach over 18,400 foxes. Round t to the nearest whole year, then state the year.

P(t) = A * (1 + r)^t

18400 = 10,100 * (1.05)^t

18400/10100 = 1.05^t

1.8217821 = 1.05^t

1.05^t = 1.8217821

In(1.05^t) = ln(1.8217821)

0.0487901 * t = 0.5998151

t = 0.5998151 / 0.0487901

t = 12.293787

Therefore eit will take 13 years

2000 + 13 = 2013

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3 years ago

Someone help!!! What is 4/5+7/8

noname [10]

Im pretty sure the answer is 1.675

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3 years ago

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Tom's stockbroker offers an investment that is compounded continuously at an annual interest rate of 3.7%. If Tom wants a return

Anettt [7]

Answer:

It'll take 38.3 years to obtain the desired return of $25,000.

Step-by-step explanation:

In order to solve a continuosly coumponded interest question we need to apply the correct formula that is given bellow:

M = C*e^(r*t)

Where M is the final value, C is the initial value, r is the interest rate and t is the time at which the money was applied. Since he wants an return of $25,000 his final value must be the sum of the initial value with the desired return. So we have:

(25000 + 8000) = 8000*e^(0.037*t)

33000 = 8000*e^(0.037*t)

e^(0.037*t) = 33000/8000

e^(0.037*t) = 4.125

ln[e^(0.037*t)] = ln(4.125)

t = ln(4.125)/(0.037)

t = 1.4171/0.037 = 38.2991

t = 38.3 years

7 0

3 years ago

Help please thank u!! ​

Help please thank u!!