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bezimeni [28]
3 years ago
15

Which point is the solution to the following system of equations

Mathematics
1 answer:
vivado [14]3 years ago
3 0
(3,2).  3^2 + 2^2 = 13   2(3)-2= 4 Works for both, hence this is the intersecting point of the two lines.
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Which of the following is the vertex of the equation \large x^2-2x=-5 ?
Lelu [443]
I think it’s C but I’m not too sure
8 0
3 years ago
The random variable x has the following probability distribution: x f(x) 0 .25 1 .20 2 .15 3 .30 4 .10 a. Is this probability di
Reptile [31]

Answer and Explanation:

Given : The random variable x has the following probability distribution.

To find :

a. Is this probability distribution valid? Explain and list the requirements for a valid probability distribution.

b. Calculate the expected value of x.

c. Calculate the variance of x.

d. Calculate the standard deviation of x.

Solution :

First we create the table as per requirements,

x      P(x)         xP(x)           x²            x²P(x)

0    0.25           0               0                0

1     0.20        0.20             1              0.20

2    0.15          0.3               4             0.6

3    0.30         0.9               9             2.7

4    0.10          0.4               16             1.6

   ∑P(x)=1     ∑xP(x)=1.8               ∑x²P(x)=5.1

a) To determine that table shows a probability distribution we add up all five probabilities if the sum is 1 then it is a valid distribution.

\sum P(X)=0.25+0.20+0.15+0.30+0.10

\sum P(X)=1

Yes it is a probability distribution.

b) The expected value of x is defined as

E(x)=\sum xP(x)=1.8

c) The variance of x is defined as

V=\sum x^2P(x)-(\sum xP(x))^2\\V=5.1-(1.8)^2\\V=5.1-3.24\\V=1.86

d) The standard deviation of x is  defined as

\sigma=\sqrt{V}

\sigma=\sqrt{1.86}

\sigma=1.136

5 0
2 years ago
Can someone quickly help me solve this ?!
Rainbow [258]

Answer: 8

Step-by-step explanation: if you count the angels and the sides then you'll get the answer 8..

7 0
3 years ago
Read 2 more answers
Suppose you solved a second-order equation by rewriting it as a system and found two scalar solutions: y = e^5x and z = e^2x. Th
xenn [34]

Answer:

The solutions are linearly independent because the Wronskian is not equal to 0 for all x.

The value of the Wronskian is \bold{W=-3e^{7x}}

Step-by-step explanation:

We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.

W = \left|\begin{array}{cc}y&z\\y'&z'\end{array}\right|

Thus replacing the functions of the exercise we get:

W = \left|\begin{array}{cc}e^{5x}&e^{2x}\\5e^{5x}&2e^{2x}\end{array}\right|

Working with the determinant we get

W = 2e^{7x}-5e^{7x}\\W=-3e^{7x}

Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.

3 0
3 years ago
Solve the simultaneous equation<br> 4x-y=9 <br> 2x-3y= -23
MrMuchimi

Answer:

x = 5

y = 11

Step-by-step explanation:

y = 4x - 9

2x -3(4x - 9) = -23

2x - 12x + 27 = -23

-10x = -23 -27

-10x = -50

minus cancels out

x = 5

y = 4(5) -9

y = 20 - 9

y = 11

4 0
2 years ago
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