All categories

2 years ago

An atom was observed with +3 charge, n = 38, and e = 28, What is the element name of the atom?

1 answer:

3 0

Hey there !

We know that

Atomic number , z = number of n+number of e

=> Z = 38+28 = 66

Hence the answer is B)Nickel-66

I hope this helps you:)
Have a good day ;)

You might be interested in

write the name of and molecular formula of compound which gives hydrogen ion and chloride ion in the solution state. in which co

VladimirAG [237]

<h3>I hope it is helpful for you .....</h3>

5 0

3 years ago

Determine how many atoms of pure silver will be created when 19.83 x 1023 atoms of copper are used in the following reaction:

Lubov Fominskaja [6]

Answer:

$\boxed{3.966 \times 10^{24}\text{ atoms of Ag}}$

Explanation:

(a) Balanced equation

Cu + 2AgNO₃ ⟶ Cu(NO₃)₂+ 2Ag

(b) Calculation

You want to convert atoms of Cu to atoms of Ag.

The atomic ratio is ratio is 2 atoms Ag:1 atom Cu

$\text{Atoms of Ag} = 19.83 \times 10^{23}\text{atoms Cu} \times \dfrac{\text{2 atoms Ag}}{\text{1 atom Cu}}\\\\= 3.966 \times 10^{24}\text{ atoms of Ag}\\\\\text{The reaction will produce }\boxed{\mathbf{3.966 \times 10^{24}}\textbf{ atoms of Ag}}$

4 0

3 years ago

Read 2 more answers

Which atomic particle determines the name of the element you build?

lyudmila [28]

Hey there!

Protons determine the name of the element you build.

Protons are the particle that determines many things about the element.

The number of protons is the atomic number of an element, which is found on the periodic table.

Hope this helps!

8 0

3 years ago

4- 4110 kg of R-134a at 300 kPa fills a rigid container whose volume is 14 L. Determine the temperature and total enthalpy in th

Nat2105 [25]

The correct question is: 10 kg of R-134a at 300 kPa fills a rigid container whose volume is 14 L. Determine the temperature and total enthalpy in the container. The container is now heated until the pressure is 600 kPa. Determine the temperature and total enthalpy when the heating is completed.

Answer: The temperature is $21.6^{o}C$ and total enthalpy when the heating is completed is 300 kJ.

Explanation:

Given: Mass = 10 kg

Volume = 14 L

Final pressure = 600 K

First, convert volume from L to $m^{3}/kg$ as follows.

$v_{1} = \frac{14 \times 10^{-3}}{10}\\= 0.0014 m^{3}/kg$

According to the R-134a tables at 300 kPa and $0.0014 m^{3}/kg$ .

$h_{1}$ = 54.6 kJ/kg

$T_{sat}$ = 0.7 C

$u_{1}$ = 54.1 kJ/kg

Now, at the state 2 $p_{2}$ = 600 kPa and $v_{2} = v_{1} = 0.0014 m^{3}/kg$

This means that the final temperature at state 2 is $T_{2} = T_{sat} = 21.6^{o}C$

Hence, the change in enthalpy is calculated as follows.

$\Delta H = m(h_{2} - h_{1})\\= 10(84.6 - 54.6)\\= 300 kJ$

The first law is applied to transfer the heat transfer as follows.

$Q = m(u_{2} - u_{1})\\= 10(83.8 - 54.1) kJ\\= 297 kJ$

Thus, we can conclude that the temperature is $21.6^{o}C$ and total enthalpy when the heating is completed is 300 kJ.

3 0

3 years ago

A 25.00 ml sample of an aqueous solution of ba(oh)2 requires 18.45 ml of 0.01500 m hcl (aq) for its neutralization. what is the

klio [65]

5.54 x 10⁻³ M

<h3>Further explanation</h3>

Given:

Neutralization reaction between:

25.00 ml of Ba(OH)₂
18.45 ml of 0.015 M HCl

Question:

What is the molarity of the Ba(OH)₂ solution?

The Process:

Let us say the molarity of the Ba (OH)₂ solution as x M.

Step-1: prepare moles for each reagent

$\boxed{ \ M = \frac{n}{V} \ }$ $\rightarrow \boxed{ \ n = MV \ }$

$\boxed{ \ Ba(OH)_2 \rightarrow n = (x \ \frac{mol}{L})(25 \ ml) = 25x \ mmol \ }$

$\boxed{ \ HCl \rightarrow n = (0.015 \ \frac{mol}{L})(18.45 \ ml) = 0.277 \ mmol \ }$

Step-2: neutralization

We use the ICE table to see how neutralization occurs between acid and base.

Balanced reaction:

$\boxed{ \ Ba(OH)_2_{(aq)} + 2HCl_{(aq)} \rightarrow BaCl_2_{(aq)} + 2H_2O_{(l)} \ }$

Initial: 25x 0.277 - -

Change: - ¹/₂ · (0.277) -0.277 +¹/₂ · (0.277) +0.277

Equlibrium: - - +¹/₂ · (0.277) +0.277

Neutralization causes no excess of hydrogen or hydroxide ions in solution. In the end, the number of acid and base reactions is balanced. In other words, the two reagents have run out with nothing left.
HCl acts as a limiting reagent.

Step-3: calculate the molarity of the Ba(OH)₂ solution.

We consider Ba (OH) from the initial, change, and equilibrium stages.

$\boxed{ \ 25x - \frac{1}{2}(0.277) = 0 \ }$

$\boxed{ \ 25x = \frac{1}{2}(0.277) \ }$

$\boxed{ \ 50x = 0.277 \ }$

$\boxed{ \ x = \frac{0.277}{50} \ }$

$\boxed{ \ x = 5.54 \times 10^{-3} \ }$

Thus, the molarity of the Ba(OH)₂ solution is 5.54 x 10⁻³ M.

_ _ _ _ _ _ _ _ _ _

Alternative Steps

Valence of base = the number of OH⁻ ions
Valence of acid = the number of H⁺ ions

Neutralization: $\boxed{ \ V_b \cdot M_b \cdot valence \ of \ base = V_a \cdot M_a \cdot valence\ of \ acid \ }$

$\boxed{ \ (25.00 \ ml) \cdot x \cdot 2 = (18.45 \ ml) \cdot (0.015 \ M) \cdot 1 \ }$

$\boxed{ \ x = \frac{(18.45 \ ml) \cdot (0.015 \ M)}{(25.00 \ ml) \cdot 2} \ }$

Thus the same results were obtained. The molarity of Ba (OH) ₂ solution is 5.54 x 10⁻³ M.

<h3>Learn more</h3>

What is the concentration of a solution formed by diluting 25.0 ml of a 3.2 M NaCl solution to 135.0 ml? brainly.com/question/12452615
How much of these solutions he needs to drain and replace with 70% acid solution to obtain 100g of 60% acid solution? brainly.com/question/7596086
How many liters of the 50% solution and how many liters of the 90% solution will be used? brainly.com/question/13034221

6 0

4 years ago