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den301095 [7]
2 years ago
7

if the maximum temperature for a particular day is 20°c and the minimum temperature is 10°c, the daily mean would be:

Chemistry
1 answer:
storchak [24]2 years ago
4 0

The daily mean, given the data from the question is 15 °C

<h3>Data obtained from the question</h3>
  • Maximum temperature = 20 °C
  • Minimum temperature = 10 °C
  • Mean = ?

<h3>How to determine the daily mean </h3>

Mean = Sumation of data / Number of data

Mean = (20 + 10) / 2

Mean = 30 / 2

Mean = 15 °C

Learn more about statistics:

brainly.com/question/8974461

#SPJ12

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water vapor. It is when water is evaporated. it can also be steam.

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If 152 grams of ethane (c2h6) are reacted with 231 grams of oxygen gas, what is the mass of the excess reactant leftover after t
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Answer is: <span>the mass of the excess reactant (ethane) leftover is 90.135 grams.
</span>Chemical reaction: 2C₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O<span>(g).
m(</span>C₂H₆) = 152 g.
n(C₂H₆) = m(C₂H₆) ÷ M(C₂H₆).
n(C₂H₆) = 152 g ÷ 30 g/mol.
n(C₂H₆) = 5.067 mol.
m(O₂) = 231 g.
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n(O₂) = 7.218 mol; limiting reactant.
From chemical reaction: n(O₂) : n(C₂H₆) = 7 : 2.
n(C₂H₆) = 2 · 7.218 mol ÷ 7.
n(C₂H₆) = 2.0625mol.
Δn(C₂H₆) = 5.067 mol - 2.0625 mol.
Δn(C₂H₆) = 3.0045 mol.
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Answer: Cl₃ > F₂ > O₂ > Ne


Explanation:


1) All the gases are at the same temperature and pressure: STP (O°, 1 atm).


2) All the gases are represented by one molecule (or mole of molecules, it is the same for our puroposes).


3) As per Avogadro's law and the ideal gas equation, the same number of particles (of any gas) occupy the same volume at the same temperature and pressure.


For example, at STP the volume of 1 mol of gas is 22.4 liter.


4) Since, density is equal to mass / volume, and you assume the same number of molecules of each gas, the order of the densities is the same that the order of the molar masses.


5) Then, you just need to state the molar mass of each gas and order in decreasing order of molar mass to have the correct order for density.


6) Molar masses:


i) Ne: 20.180 g/mol


ii) O₂: 2× 15.999 g/mol = 31.998 g/mol


iii) F₂: 2×18.998 g/mol = 37.996 g/mol


iv) Cl₃: 3×35.453 g/mol = 106.359


7) Then the order is: 106.359 > 37.996 > 31.998 > 20.18 ⇒ is Cl₃ > F₂ > O₂ > Ne.


Note: the values calculate are not of densities but of molar masses. The order is what is the same.

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