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IRINA_888 [86]
3 years ago
6

write the name of and molecular formula of compound which gives hydrogen ion and chloride ion in the solution state. in which co

lour is the methyl orange changed after treating it with this compound. why? write the name of salt when the compound is treated with lime water. write the chemical equation. ​
Chemistry
1 answer:
VladimirAG [237]3 years ago
5 0
<h3>I hope it is helpful for you .....</h3>

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Compared to 1 liter aqueous solution with a ph of 7, a 1 liter aqueous solution with a ph of 5.0 contains
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Each unit of pH represents a change by a factor of 10. Thus in a pH of 5, there would be 100x the concentration of Hydrogen ions in solution.

The correct option would be 2.
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When aqueous solutions of HCl and NaOH are mixed together in a calorimeter, the temperature of the solution increases. The react
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This reaction is exothermic because the system (the aqueoud solution) is transferring heat to its surroundings (the calorimeter) so this eliminates two responses. Since the heat is being transferred to the surroundings, the water that's in the calorimeter in this case, it is causing the water molecules to heat up and thus an increase in the kinetic energy of the water molecules since temperature affects kinetic energy
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Elements whose names end with âium are usually metals; sodium is one example. Identify a nonmetal whose name also ends with âium
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Answer: Helium (He) and Selenium (Se) both are non metals ends with ium sound

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8 0
3 years ago
What would be the freezing point of a solution that has a molality of 1.324 m which was prepared by dissolving biphenyl (C12H10)
lbvjy [14]

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

A solution is prepared by dissolving biphenyl into naphthalene. We can calculate the freezing point depression (ΔT) for naphthalene using the following expression.

\Delta T = i \times Kf \times m =   1 \times 6.90 \°C/m  \times 1.324m = 9.14  \°C

where,

  • i: van 't Hoff factor (1 for non-electrolytes)
  • Kf: cryoscopic constant
  • m: molality

The normal freezing point of naphthalene is 80.26 °C. The freezing point of the solution is:

T = 80.26 \° C - 9.14 \° C = 71.12 \° C

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

Learn more: brainly.com/question/2292439

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2 years ago
How spectral lines are formed
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=Spectral lines are produced by transitions of electrons within atoms or ions. As the electrons move closer to or farther from the nucleus of an atom (or of an ion), energy in the form of light (or other radiation) is emitted or absorbed.…

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2 years ago
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