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Art [367]
2 years ago
8

Which of the following is true for a chemical reaction at equilibrium?

Chemistry
1 answer:
victus00 [196]2 years ago
7 0

Answer:

youre gonna have to include the answers for me to help

Explanation:

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PLEASE HELP! NO LINKS! CHEMISTRY!
Bingel [31]

Answer:

Solution A is 1,000 times more acidic than Sol. B

Explanation:

for pH values we use scientific notation:

-log10 c (where c is the hydrogen ion concentration) is used to notate pH value (think of it as a unit)

ie:

10^-2 is sol A 10^-5 is sol B

5-2 is 3

10^-3 = 1000

there's a diff of 1,000 between the solutions.

6 0
3 years ago
Read 2 more answers
Describe an acid or base in terms of its relationship to protons
motikmotik
Acids are donors of protons (H+) and bases are acceptors of protons.
For example:
1) hydrochloric acid (HCl) in reaction with water give one proton to water and become chloride anion (Cl-).
2) ammonia (NH3) Is base, in reaction with water accepts one protone and become ammonium cation (NH4+).
4 0
3 years ago
Calculate the mass in micrograms of zinc oxalate the chemist has added to the flask. be sure your answer has the correct number
Vera_Pavlovna [14]
<span>A chemist adds 155.0ml of a 4.10 X 10^-5 mmol/L of a zinc oxalate (ZnC2O4)solution to a reaction flask. Calculate the mass in micrograms of zinc oxalate the chemist has added to the flask. 1mmol = 10^-3 mol Therefore 4.10*10^-5mmol = 4.10*10^-8mol molar mass ZnC2O4 = 65.39+(2*12.011)+(4*15.99) = 153.372g/mol You have 4.10*10^-8 mol/litre =153.372 * 4.10*10^-8 = 6.29*10^-6 grams / litre (* see below) But you have 155ml. Mass of ZnC2O4 = 155/1000*6.29*10^-6 g Mass is = 9.75*10^-7 grams 1µg = 10^-6 g You then have 9.75*10^-7/10^-6 = 0.975µg ZnC2O4 (*see below) at this point you could have said: 1µg = 10^-6 g therefore you have a solution of 6.29µg per litre, 155ml = 6.29*155/1000 = 0.975µg ZnC2O4</span>
3 0
3 years ago
How many moles of nitroge are there in 50.0 g of nitrogen?
chubhunter [2.5K]

1.785714286 moles

The number of moles (n) for nitrogen is: [ n=50.0÷28.0 ] = 1.785714286 moles.

8 0
3 years ago
Calculate in gramm the mass of 0.1 mole of hydrochloric acid(h=1 ,cl=35.5)​
babunello [35]

Answer:

mass of HCl = 3.65 g

Explanation:

Data Given:

Moles of hydrochloric acid HCl = 0.1 mole

Mass in grams of hydrochloric acid HCl = ?

Solution:

Mole Formula

                  no. of moles = Mass in grams / molar mass

To find Mass in grams rearrange the above Formula

                Mass in grams = no. of moles x molar mass . . . . . . . (1)

Molar mass of HCl = 1 + 35.5 = 36.5 g/mol

Put values in equation 1

              Mass in grams = 0.1 mole x 36.5 g/mol

              Mass in grams = 3.65 g

mass of HCl = 3.65 g

6 0
3 years ago
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