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Art [367]
2 years ago
8

Which of the following is true for a chemical reaction at equilibrium?

Chemistry
1 answer:
victus00 [196]2 years ago
7 0

Answer:

youre gonna have to include the answers for me to help

Explanation:

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How much energy (kJ) is required to change 0.18 mole of ice (s) at 0 C to water (l) at 0 C?
Dmitriy789 [7]

Answer:25,06 kJ of energy must be added to a 75 g block of ice.

ΔHfusion(H₂O) = 6,01 kJ/mol.

T(H₂O) = 0°C.

m(H₂O) = 75 g.

n(H₂O) = m(H₂O) ÷ M(H₂O).

n(H₂O) = 75 g ÷ 18 g/mol.

n(H₂O) = 4,17 mol.

Q = ΔHfusion(H₂O) · n(H₂O)

Q = 6,01 kJ/mol · 4,17 mol

Q = 25,06 kJ.

Explanation:

6 0
2 years ago
According to the following reaction, how many grams of hydrogen
Mila [183]

Answer:

7.03 g

Explanation:

Step 1: Write the balanced synthesis reaction

N₂(g) + 3 H₂(g) ⇒ 2 NH₃(g)

Step 2: Calculate the moles corresponding to 32.5 g of N₂

The molar mass of N₂ is 28.01 g/mol.

32.5 g × 1 mol/28.01 g = 1.16 mol

Step 3: Calculate the number of moles of H₂ needed to react with 1.16 moles of N₂

The molar ratio of N₂ to H₂ is 1:3. The moles of H₂ needed are 3/1 × 1.16 mol = 3.48 mol.

Step 4: Calculate the mass corresponding to 3.48 moles of H₂

The molar mass of H₂ is 2.02 g/mol.

3.48 mol × 2.02 g/mol = 7.03 g

8 0
3 years ago
Heavy snowfall combined withholding blowing snow results in a(n)
sukhopar [10]

Answer:

D

Explanation:

7 0
3 years ago
Read 2 more answers
Where might you find a temperature of 2 kelvin?
lyudmila [28]
100°C is 273 kelvins.

1°C is 2.73 kelvins.

I guess the closest would be north pole
7 0
3 years ago
What is the force exerted if a 52kg student accelerates into their desk at 5/ms2
murzikaleks [220]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{260 \: newton}}}}}

Explanation:

Mass ( m ) = 52 kg

Acceleration ( a ) = 5 m / s²

Force ( F ) = ?

According to Newton's second law of motion ,

\boxed{ \sf{force = mass \times acceleration}}

\longrightarrow{ \sf{force = 52  \times 5}}

\longrightarrow{ \sf{force = 260 \: newton}}

Hope I helped!

Best regards! :D

3 0
3 years ago
Read 2 more answers
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