Answer:
The mixture contains 8.23 g of Ar
Explanation:
Let's solve this with the Ideal Gases Law
Total pressure of a mixture = (Total moles . R . T) / V
We convert T° from °C to K → 85°C + 273 = 358K
3.43 atm = (Moles . 0.082 L.atm/mol.K . 358K) / 6.47L
(3.43 atm . 6.47L) / (0.082 L.atm/mol.K . 358K) = Moles
0.756= Total moles from the mixture
Moles of Ar + Moles of H₂ = 0.756 moles
Moles of Ar + 1.10 g / 2g/mol = 0.756 moles
Moles of Ar = 0.756 moles - 0.55 moles H₂ → 0.206
We convert the moles to g → 0.206 mol . 39.95 g / 1 mol = 8.23 g
<h3>
Answer:</h3>
52 mm
<h3>
Explanation:</h3>
We are given;
Required to convert it to cm
We are going to use the appropriate conversion factor;
- The units used to measure length include;
Kilometer(km)
10
Hectometer (Hm)
10
Decameter (dkm)
10
Meter(m)
10
Decimeter (dm)
10
Centimeter (cm)
10
Millimeter (mm)
Therefore; the appropriate conversion factor is 10mm/cm
Thus;
5.2 cm will be equivalent to;
= 5.2 cm × 10 mm/cm
= 52 mm
Therefore, the length of magnesium ribbon is 52 mm
Answer:
The answer is IONIC BOND
Explanation:
Steroidogenic acute regulatory, (StAR) protein is a type of globular protein, which allows it act as an active catalyst on substrates. Because the substrates on which enzymes act usually have higher molecular weights of several hundred as compared to the enzymes, only a fraction of the enzyme's surface is in contact with the substrate. This region of contact called the <em>active site</em>, is as a result of the protein folding itself into a tertiary structure.
Once the correct substrate has bound at the active site of the enzyme, an enzyme-substrate complex is created. The substrate is usually held in the complex by combinations of electrical attraction, hydrophobic repulsion, or hydrogen bonding between and from the amino acid; the strongest of which is the ionic/electrostatic bonding due to larger amount of ionic "R" groups in the protein structure.
So whilst all these inter-molecular interactions are possible, the strongest would be <u>ionic bond.</u>
It will be Solvent the term that would describe the alcohol will be solvent.
Answer:
n₂ = 2.55 mol
Explanation:
Given data:
Initial number of moles = 0.758 mol
Initial volume = 80.6 L
Final volume = 270.9 L
Final number of moles = ?
Solution:
Formula:
V₁/n₁ = V₂/n₂
V₁ = Initial volume
n₁ = initial number of moles
V₂ = Final volume
n₂ = Final number of moles
now we will put the values in formula.
V₁/n₁ = V₂/n₂
80.6 L / 0.758 mol = 270.9 L/ n₂
n₂ = 270.9 L× 0.758 mol / 80.6 L
n₂ = 205.34 L.mol /80.6 L
n₂ = 2.55 mol
