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Scrat [10]
3 years ago
5

Insoluble sulfide compounds are generally black in color.

Chemistry
1 answer:
AfilCa [17]3 years ago
5 0
<h3>Answer:</h3>

Li₂S(aq)+Pb(NO₃)₂(aq) → PbS(s) + LiNO₃(aq)

K2S(aq)+Sn(NO₃)₄(aq→ SnS(s) + KNO₃(aq)

<h3>Explanation:</h3>
  • According to solubility rules, metal sulfides are insoluble except Calcium sulfide(CaS), Magnesium sulfide(MgS), Barium sulfide(BaS), and those of potassium, sodium, and ammonium.
  • Therefore, when all the other sulfides are formed during a reaction they form a precipitate that is shown to be in solid-state.
  • Precipitates are formed during precipitation reactions when cations and anions combine to form a compound that is insoluble in water.

In our case; In the equations given, some reactions will take place to form a precipitate while others will not occur.

That is;

  • Na₂S(aq)+KCl(aq) → No reaction
  • Li₂S(aq)+Pb(NO₃)₂(aq) → PbS(s) + LiNO₃(aq)
  • Pb(ClO₃)₂(aq)+NaNO₃(aq) → No reaction
  • AgNO₃(aq)+KCl(aq) →AgCl(s) + KNO₃(aq)
  • K2S(aq)+Sn(NO₃)₄(aq→ SnS(s) + KNO₃(aq)

The first reaction will not occur.

The second equation is a precipitation reaction that forms lead(ii)sulfide which is a black precipitate.

The third reaction will not take place.

The fourth reaction will be a precipitation reaction forming silver chloride precipitate.

The fifth equation is also a precipitation reaction that forms tin(ii) sulfide, SnS which is a black precipitate.

Therefore; the equations that answers our question are;

  • Li₂S(aq)+Pb(NO₃)₂(aq) → PbS(s) + LiNO₃(aq)
  • K2S(aq)+Sn(NO₃)₄(aq→ SnS(s) + KNO₃(aq)
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