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Scrat [10]
3 years ago
5

Insoluble sulfide compounds are generally black in color.

Chemistry
1 answer:
AfilCa [17]3 years ago
5 0
<h3>Answer:</h3>

Li₂S(aq)+Pb(NO₃)₂(aq) → PbS(s) + LiNO₃(aq)

K2S(aq)+Sn(NO₃)₄(aq→ SnS(s) + KNO₃(aq)

<h3>Explanation:</h3>
  • According to solubility rules, metal sulfides are insoluble except Calcium sulfide(CaS), Magnesium sulfide(MgS), Barium sulfide(BaS), and those of potassium, sodium, and ammonium.
  • Therefore, when all the other sulfides are formed during a reaction they form a precipitate that is shown to be in solid-state.
  • Precipitates are formed during precipitation reactions when cations and anions combine to form a compound that is insoluble in water.

In our case; In the equations given, some reactions will take place to form a precipitate while others will not occur.

That is;

  • Na₂S(aq)+KCl(aq) → No reaction
  • Li₂S(aq)+Pb(NO₃)₂(aq) → PbS(s) + LiNO₃(aq)
  • Pb(ClO₃)₂(aq)+NaNO₃(aq) → No reaction
  • AgNO₃(aq)+KCl(aq) →AgCl(s) + KNO₃(aq)
  • K2S(aq)+Sn(NO₃)₄(aq→ SnS(s) + KNO₃(aq)

The first reaction will not occur.

The second equation is a precipitation reaction that forms lead(ii)sulfide which is a black precipitate.

The third reaction will not take place.

The fourth reaction will be a precipitation reaction forming silver chloride precipitate.

The fifth equation is also a precipitation reaction that forms tin(ii) sulfide, SnS which is a black precipitate.

Therefore; the equations that answers our question are;

  • Li₂S(aq)+Pb(NO₃)₂(aq) → PbS(s) + LiNO₃(aq)
  • K2S(aq)+Sn(NO₃)₄(aq→ SnS(s) + KNO₃(aq)
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If 650. grams of C6H12O6 (FW 180.16) reacts with 650. grams of O2 (FW 32.00) in cellular respiration: C6H12O6 6 O2 --&gt; 6 CO2
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Answer:

O2 is limiting reactant

Explanation:

To find the limiting reactant we need to convert the mass of each reactant to the moles using the formula weight. And, as 1 mole of C6H12O6 reacts with 6 moles of O2, we can know wich reactant will be over first (Limiting reactant) as follows:

<em>Moles C6H12O6:</em>

650g * (1mol/180.16g) = 3.608 moles C6H12O6

<em>Moles O2:</em>

650g * (1mol/32g) = 20.31 moles O2

Now, for a complete reaction of 3.608 moles of C6H12O6 are required:

3.608 moles C6H12O6 * (6mol O2 / 1mol C6H12O6) = 21.65 moles O2

As there are just 20.31 moles of O2,

<h3>O2 is limiting reactant</h3>
4 0
2 years ago
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Ostrovityanka [42]

Answer:

NaCl + AgF → NaF + AgCl

Explanation:

A double replacement reaction is a type of chemical reaction that occurs when two reactants exchange cations or anions to yield two new products.

From all the reactions given ,

  • 2Na + Cl₂ → 2NaCl is an example of combination reaction because two or more reactants (Na & Cl₂) react with each other to form a single product (NaCl)
  • H₂SO₃ → H₂O + SO₂ is an example of decomposition reaction because a single reactant (H₂SO₃) breaks down into two or more products (H₂O & SO₂).
  • 2K + 2H₂O → 2KOH + H₂ is an example of displacement reaction because a highly reactive element (K) displaces a least reactive element (H) from its compound (H₂O).
  • NaCl + AgF → NaF + AgCl is an example of double replacement reaction because there's an exchange between Cations (Na^+ & Ag^{+}) and Anions (Cl^- & F^-).
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Answer:

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Explanation:

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