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SOVA2 [1]
4 years ago
8

Which statements describe what happens in a redox reaction? Check all that apply. A. Electrons move from one substance to anothe

r. B. One atom gains electrons and one loses electrons. C. The cations on two substances trade places. D. There are two oxidation reactions.
Chemistry
2 answers:
Strike441 [17]4 years ago
6 0
A redox reaction is a reaction that involves both reduction and oxidation, it involves a reducing agent which looses electrons and undergoes oxidation and an oxidizing agent that gains electrons (reduction). I believe the following are true about redox reactions; Electrons move from one substance to another, One atom gains electrons and one looses electrons.
vfiekz [6]4 years ago
3 0

<u>Answer:</u> The correct answers are Option A and Option B.

<u>Explanation:</u>

Oxidation-reduction reaction or redox reaction is the reaction in which oxidation and reduction reactions occur simultaneously.

Oxidation reaction is the reaction in which an atom looses its electrons. The oxidation state of the atom increases.

X\rightarrow X^{n+}+ne^-

Reduction reaction is defined as the reaction in which an atom gains electrons. The oxidation state of the atom gets reduced.

X^{n+}+ne^-\rightarrow X

In a redox reaction, one atom gain electron and another atom looses electron or it can also be said that electrons are transferred from one substance to another substance.

Thus, the correct answers are Option A and Option B.

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Amphetamine (c9h13n) is a weak base with a pkb of 4.2. calculate the ph of a solution containing an amphetamine concentration of
soldier1979 [14.2K]

Answer:

pH = 10.505

Explanation:

Molar mass of Amphetamine ( C9H13N) = 135 g/mol

Given that the concentration of Amphetamine = 225 mg/L

mass of Amphetamine in one Liter = \frac{225}{ 1000} = 0.225 g

Number of moles of Amphetamine in one liter =\frac {0.225 g} { 135g/mol}

= 0.001667 mol

∴ molarity = 0.0017 M

              C₉H₁₃N          +        H₂O -------->       C₉H₁₃NH⁺  +      OH⁻

I(M)         0.001667   M                                                  0                 0

C(M)            -x                                                                  x                 x

E(M)         0.001667 - x                                                   x                 x

Pkb = -log Kb = 4.2

∴ Kb = 6.309 x 10⁻⁵

Kb = 6.309 x 10⁻⁵

Equilibrium constant  = [C₉H₁₃NH⁺][OH⁻]/ [C₉H₁₃N]

6.309 x 10⁻⁵  = x² / 0.001667-x

where 0.001667 -x ≅ 0.001667

Then;

x² = 6.309 x 10⁻⁵  × 0.001667

x² =  1.0517103 × 10⁻⁷

x = \sqrt {1.0517103 * 10^{-7}

x = 0.00032 M

x = [OH-] = 0.00032 M

∴ pOH = -log [OH-]

pOH = -log (0.00032)

pOH =3.495

pH = 14 - 3.495

= 10.505

4 0
4 years ago
Where are gummy bears made?
Natalija [7]
Gummy bears are made in a special factory with many different tools in it that process the gummy bears
6 0
3 years ago
if nitrogen, which has an electronegativity of 2.0, bonds with hydrogen, which has an electronegativity of 2.1, the bond between
kirill [66]

Answer:

Polar covalent bond because of difference in electronegativities

Explanation:

6 0
3 years ago
Read 2 more answers
A 58.33-g sample of milk of magnesia, Mg(OH)2, always contains 24.31g of magnesium, 32.00g of oxygen, and 2.02g of hydrogen. Fin
ASHA 777 [7]

The mass percentage of each element in the milk of magnesia is, 41.68% Mg, 54.86% Oxygen, and 3.46% Hydrogen elements

Give the total mass of a sample of milk of magnesia Mg(OH)₂ as 58.33 g

We are to calculate the percentage by mass of each element

\% mass =\frac{mass \ of \ element}{mass \ of \ sample} \times 100

For Magnesium:

Mass of magnesium = 24.31g

\% mass \ of \ Mg = \frac{24.31}{58.33} \times 100\\ \% mass \ of \ Mg =\frac{2431}{58.33} \\ \% mass \ of \ Mg = 41.68\%

For oxygen element:

Mass of oxygen = 32.00g

\% mass \ of \ O_2 = \frac{32}{58.33} \times 100\\ \% mass \ of \ O_2 =\frac{3200}{58.33} \\ \% mass \ of \ O_2 = 54.86\%

For the hydrogen element

Mass of hydrogen = 2.02g

\% mass \ of \ H_2 = \frac{2.02}{58.33} \times 100\\ \% mass \ of \ H_2 =\frac{202}{58.33} \\ \% mass \ of \ H_2 = 3.46\%

Hence the mass percentage of each element in the milk of magnesia is, 41.68% Mg, 54.86% Oxygen, and 3.46% Hydrogen elements.

Learn more here: brainly.com/question/20065048

5 0
3 years ago
A 0.568-g sample of fertilizer contained nitrogen as ammonium sulfate, . It was analyzed for nitrogen by heating with sodium hyd
Mariulka [41]

Answer:

6.69%

Explanation:

Given that:

Mass of  the fertilizer = 0.568 g

The mass of HCl used in titration (45.2 mL of 0.192 M)

= 0.192*\frac{45.2}{1000}* \frac{36.5}{1 \ mole}

= 0.313 g HCl

The amount of NaOH used for the titration of excess HCl (42.4 mL of 0.133M)

= \frac{44.3 \ mL * 1.0 \ L}{1000 \ mL} *0.133 \ mole/L

= 0.0058919 mole of NaOH

From the neutralization reaction; number of moles of HCl is equal with the number of moles of NaOH is needed to complete the neutralization process

Thus; amount of HCl neutralized by 0.0058919 mole of NaOH = 0.0058919 × 36.5 g

= 0.2151 g HCl

From above ; the total amount of HCl used = 0.313 g

The total amount that is used for complete neutralization = 0.2151 g

∴ The amount of HCl reacted with NH₃ = (0.313 - 0.2151)g

= 0.0979 g

We all know that 1 mole of NH₃ = 17.0 g , which requires 1 mole of HCl = 36.5 g

Now; the amount of HCl neutralized by 0.0979 HCl = \frac{17}{36.5}*0.0979

= 0.0456 g

Therefore, the mass of nitrogen present in the fertilizer is:

= 0.0456 \ g \ NH_3 * \frac{1  \ mol \ NH_3 }{17.0 \ mol \ of \ NH_3} * \frac{1  \mol \ (NH_4)_2SO_4}{2 \ mol \ NH_3 } * \frac{2 \ mol \ N }{1  \mol \ (NH_4)_2SO_4}* \frac{14.0 g }{1 \ mol \ N}

= 0.038 g

∴ Mass percentage of Nitrogen in the fertilizer = \frac{0.038 \ g}{0.568 \ g} * 100%

= 6.69%

8 0
4 years ago
Read 2 more answers
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