The empirical formula is C₃H₃O.
Moles of C = 65.5/12.01
= 5.45 mol C
Moles of H = 5.5/1
= 5.5 mol H
Moles of O = 29.0/16
= 1.81 mol H
Moles of C: Moles of H: Moles of O =5.45: 5.5: 1.81 =
3.01: 3.0: 1 ≈ 3:3: 1
The empirical formula is C₃H₃O.
Answer:
it is in liquid state.
it shapes as the object is .
it can change into gas state by heating .
it has on colour.
Answer:
Kindly check Explanation
Explanation:
Given the chemical equation:
2 Mg(s) + O2(g) → 2 MgO(s)
2 molecules of Magnesium + Oxygen gas (Reactant)
→ ( yield)
2 molecules of magnesium oxide (product)
2 in Mg and MgO (coefficients)
2 in Oxygen gas (subscript)
Solid (s) - physical state of Reactant Mg
Gas (g) - physical state of Reactant O2
Solid (s) - physical state of product 2MgO
Answer:
92.87 g.
Explanation:
∵ The percentage yield = (actual yield/theoretical yield)*100.
- We need to calculate the theoretical yield:
From the balanced reaction:
<em>PCl₃ + Cl₂ → PCl₅,</em>
It is clear that 1 mol of PCl₃ reacts with 1 mol of Cl₂ to produce 1 mol of PCl₅.
- We need to calculate the no. of moles of 73.7 g PCl₃:
n = mass/molar mass = (73.7 g)/(137.33 g/mol) = 0.536 mol.
<u><em>Using cross multiplication:</em></u>
1 mol of PCl₃ produce → 1 mol of PCl₅, from stichiometry.
∴ 0.536 mol of PCl₃ produce → 0.536 mol of PCl₅.
∴ The mass of PCl₅ (theoretical yield) = (no. of moles) * (molar mass) = (0.536 mol)*(208.24 g/mol) = 111.62 g.
<em>∵ The percentage yield = (actual yield/theoretical yield)*100.</em>
The percentage yield = 83.2%, theoretical yield = 111.62 g.
∴ The actual yield of PCl₅ = (The percentage yield)(theoretical yield)/100 = (83.2%)(111.62 g)/100 = 92.87 g.
Answer:
Becuase CH30 has weaker inter-molecular forces
Explanation:
Becuase its intermolecular forces are weaker the particals will seperate more easilyl.
